Answer:
temperature on left side is 1.48 times the temperature on right
Explanation:
GIVEN DATA:
T1 = 525 K
T2 = 275 K
We know that
n and v remain same at both side. so we have
..............1
let final pressure is P and temp 
..................2
similarly
.............3
divide 2 equation by 3rd equation
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)
thus, temperature on left side is 1.48 times the temperature on right
Answer:
See the explanation below.
Explanation:
The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.
![F_{1x}=30.8*cos(20)\\F_{1x}=28.94[N]\\F_{2x}=34.3*cos(20)\\\\F_{2x}= 32.23[N]](https://tex.z-dn.net/?f=F_%7B1x%7D%3D30.8%2Acos%2820%29%5C%5CF_%7B1x%7D%3D28.94%5BN%5D%5C%5CF_%7B2x%7D%3D34.3%2Acos%2820%29%5C%5C%5C%5CF_%7B2x%7D%3D%2032.23%5BN%5D)
Answer:
thermal energy
Friction does negative work and removes some of the energy the person expends and converts it to thermal energy. The net work equals the sum of the work done by each individual force. The forces acting on the package are gravity, the normal force, the force of friction, and the applied force.
Explanation:
