Answer:
Since both Anthony and Sara are healthy carriers of the gene that causes cystic fibrosis, the chance of having a child with this disease are 1:4 (option D).
Explanation:
The inheritance pattern of cystic fibrosis is autosomal recessive, and considering that both parents carry the abnormal CFTR gene, it can be said that the parental genotypes are:
<em>Anthony N/Qf
</em>
<em>Sara N/Qf
</em>
Where N is the normal gene and Qf is the abnormal gene.
Since this is an autosomal recessive disorder, only the homozygosity of the defective allele will cause the disease to manifest
:
N/Qf X N/Qf
<em>Alleles N Qf
</em>
<em>N N/N N/Qf
</em>
<em>Qf N/Qf Qf/Qf
</em>
- The chances of having a healthy child are 25%.
- The chances of having a carrier child are 50%.
- The chances of having a child with cystic fibrosis are 25%.
Therefore, the chance of Anthony and Sara having a child with cystic fibrosis is 1:4.
Learn more:
Cystic fibrosis inheritance brainly.com/question/6584627
In humans<span>, </span>each cell<span> normally contains 23 pairs of </span>chromosomes<span>, for a total of 46.
</span>
Answer:
Adenine (A) with Thymine(T)
Cytosine(C) with Guanine(G)
