Answer:
<h2>
Haploid=13</h2><h2>
triploid=39 </h2><h2>
tetraploid=52</h2><h2>
trisomic=14 </h2><h2>
monosomic=12</h2>
Explanation:
Given;
A species with a diploid number of 26, so 26= 2n ( a diploid cell),
so in haploid condition, chromosome number becomes half (13 in this case). triplod is when 2n + n, and 2n +2n ( tetploid). Trisomy and monosomy is the addition or deletion of a sinlge chromosome of a sinlge set .
Haploid=13, one chromosome from each pair of chromosome set,
triploid=39 (13× 3); diploid+ n( 3n)
tetraploid=52 (13× 4) 4n
trisomic=14 (13+1) ; n+1
monosomic=12 (13-1); n-1
The correct answer is A. When free hydrogen ions and free hydroxyl ions are removed from solutions of acids and bases, the acidic and basic properties disappear.
The strength of the acid or base depends upon its degree of ionization. Since different acids and different bases dissociate or ionize to different extent in water so their degree of ionization is also different. Strong acids and strong bases ionize in water completely while the weaker acids or bases ionize partially. Ionization of the weak acids in water are in equilibrium. The degree of ionization is the ratio of the number of ionized molecules to the number of molecules which are dissolved in water. In case of acids the ionized molecules are hydrogen ions and in case of bases hydroxyl ions.
<span>During meiosis I, homologous chromosome pairs are separated when the centromeres split apart.
This answer would be false.</span>
c. It never changes during the experiment.
