Yes it is a solution because if you take the equation and plug the point in for the x and y :
4 (2) + 3 (3) < 20
8 + 9 < 20
17 < 20
which is true
10 (2) + (3) > 10
20 + 3> 10
23>10
which is also true
Answer:
Part A:
(2x+7)(5x+9)
=(2x+7)(5x+9)
=(2x)(5x)+(2x)(9)+(7)(5x)+(7)(9)
=10x2+18x+35x+63
=10x2+53x+63
A)
The formula for determining the area of a rectangle is given as
Area = length × width
Given that the length and width are (2x + 6) units and (5x + 3) units, the expression for the area is
(2x + 6)(5x + 3) = 10x² + 6x + 30x + 18
Area = 10x² + 36x + 18
B)
The degree is 2 because the highest power of the terms is 2. It is classified as a trinomial because it has 3 terms.
C) it is closed under multiplication. the exponents in the polynomials are whole numbers(2 and 1). The whole numbers are closed under addition, which means that the new exponents formed are also whole numbers. The exponents were whole numbers before multiplication and doesn't change after multiplication.
Step-by-step explanation:
I don’t understand your question can you go into more detail please
No -4/3 can not be simplified
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian :
Akar-akar persamaan lama : x1 dan x2
Akar-akar persamaan baru : xA dan xB
xA = 2x1 - 1
xB = 2x2 - 1
xA + xB = (2x1 - 1) + (2x2 - 1)
= 2 (x1 + x2) - 2
= 2 () - 2
= 3 - 2
xA + xB = 1
xA . xB = (2x1 - 1) (2x2 - 1)
= 4 x1.x2 - 2(x1 + x2) + 1
= 4.(-) - 2() + 1
= -2 - 3 + 1
xA . xB = -4
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
x² - x - 4 = 0
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