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KonstantinChe [14]
3 years ago
7

What is an equation of the line that passes through the points (4,-2) and (8,3)?

Mathematics
1 answer:
gladu [14]3 years ago
5 0

the other is the same as the other o li and the other o li and the other o li and the other o li and the other o li and has been the best selling game in my history for a while and it is not the best time for me the whole time I was a new York fan who was so excited to see my new album in my first impres and the next episode I had to get out yet and still haven't had to do anything for a long

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Question 1 Part B (3 points): Using the GCF that you chose in part A, factor that GCF out of the polynomial:
Aleks [24]

The factor of the polynomial 18x³ + 6x²y - 9x² - 3xy will be 3x(6x² - 2xy - 3x - y). Then the correct option is C.

<h3>What is a factorization?</h3>

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The polynomial is given below.

⇒ 18x³ + 6x²y - 9x² - 3xy

Then the factor of the polynomial will be

⇒ 18x³ + 6x²y - 9x² - 3xy

⇒ 3x(6x² - 2xy - 3x - y)

More about the factorization link is given below.

brainly.com/question/6810544

#SPJ1

5 0
2 years ago
Find the expansion of tan x about the point X = 0.
yan [13]

Answer:

f(x) = x +\frac{1}{3}x^{3}+....

Step-by-step explanation:

As per the question,

let us consider f(x) = tan(x).

We know that <u>The Maclaurin series is given by:</u>

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

So, differentiate the given function 3 times in order to find f'(x), f''(x) and f'''(x).

Therefore,

f'(x) = sec²x

f''(x) = 2 × sec(x) × sec(x)tan(x)

      = 2 × sec²(x) × tan(x)

f'''(x) = 2 × 2 sec²(x) tan(x) tan(x) + 2 sec²(x) × sec²(x)

       = 4sec²(x) tan²(x) + 2sec⁴(x)

       = 6 sec⁴x - 4 sec² x

We then substitute x with 0, and find the values

f(0) = tan 0 = 0

f'(0) =  sec²0 = 1

f''(0) = 2 × sec²(0) × tan(0) = 0

f'''(0) = 6 sec⁴0- 4 sec² 0 = 2

By putting all the values in the Maclaurin series, we get

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

f(x) = 0 + \frac{1}{1}\cdot x+ \frac{0}{2}\cdot x^{2}+\frac{2}{6}\cdot x^{3}+......

f(x) = x +\frac{1}{3}x^{3}+....

Therefore, the expansion of tan x at x = 0 is

f(x) = x +\frac{1}{3}x^{3}+.....

8 0
3 years ago
F(x)=4x-9? when the value is f(-3)
Bingel [31]
The answer is in the picture

8 0
3 years ago
What is the median for the set of data?<br><br> A. 70<br> B. 71<br> C. 72<br> D. 74
larisa [96]

Answer:

Median = 72

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do you translate a figure in a coordinate plane
Helga [31]

To translate a figure on a coordinate plane, it is basically moving it so many units horizontally or so many units vertical by counting the amount of units you have on weather it is positive or negative. If it looks like (7,-2) The 7 is your x value, so you would move it 7 to the right and place your first point there and do that to the rest of your points. Now the -2 is your y value, so you would move your first point down 2 and do that to the rest of your points!


3 0
3 years ago
Read 2 more answers
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