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pickupchik [31]
3 years ago
12

Suppose Kalvin spins the pointer 64 times. Based on your experiment, how many times can you expect the pointer to land on 9:00,

on 10:00 and on 11:00?
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

16 times out of 64

Step-by-step explanation:

So, I could be wrong, but basically:

9, 10, and 11 are only 3 of the 12 possible outcomes that could happen.

3 out of 12 is 1/4.

What this means is that for every 4 times he spins the pointer, he can expect to get 9, 10, or 10 once.

Or 25% of the time

1/4 of 64 is 16.

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Which expressions have a value of 1/2?
tangare [24]
A) 8/16 = 1/2; YES

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D) 2^1 = 2; NO

Hope this helped!
7 0
3 years ago
Read 2 more answers
True or false in the body of an indirect proof you must show that the assumption leads to a contradiction
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3 years ago
I really really really need help!!!!
Yakvenalex [24]
For f to be continuous at x=1, you need to have the limit from either side as x\to1 to be the same.

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b

If a=2 and b=3, then the limit from the right would be 2+3=5\neq2, so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation a+b=2.

Part (c) is done similarly to part (1). This time, you need to limits from either side as x\to2 to match. You have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b
\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0

So, a and b have to satisfy the relation 4a+2b=0, or 2a+b=0.

Part (4) is done by solving the system of equations above for a and b. I'll leave that to you, as well as part (5) since that's just drawing your findings.
8 0
2 years ago
Which student wrote an expression equivalent to 6x + 4x to the third power? Choose all that apply.
FinnZ [79.3K]
Bart and David are correct. 
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David
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x*6 = 6x
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6x+4x^3

7 0
2 years ago
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