Answer:
the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Explanation:
Given the data in the question;
sound intensity reduced by the factor, m = 305
the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB
Now, using the expression of sound intensity level;
L = 10log( )
where is the intensity at L level
so we substitute
79 = 10log( )
=
Now, expression for actual intensity;
= m
where is the actual intensity
so we substitute
= 305 ×
Next, we write the expression of sound intensity level for reduced intensity;
L' = 10log( )
So we substitute
L' = 10log( 305 × )
L' = 10log( 24227011159.09058 )
L' = 103.8 dB
Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Answer:
Final angular velocity = 2.15rad/s
Explanation:
The final angular velocity can be determined using the equation:
L=Ii × wi
L= (Ii + II) × wf
Where I is the moment of inertia of the 2nd cylinder and wf is the final angular velocity.
Given:
Ii=12.6kgm^2
I=41.8kgm^2
Wi=9.28rad/s
Ii ×wi= (Ii + I)×wf
12.6×9.28 = (12.6+41.8)×wf
116.93= 54.4wf
Wf=116.93/54.4
Wf= 2.15rad/s
The level and type of impairment determine the severity and location of the injury.