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emmasim [6.3K]
3 years ago
14

By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect

the earth's rotational effects
Physics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

Weight\ loss=1.6321N

Explanation:

From the question we are told that:

Weight W=85.9kg

Altitude h= 6.33 km

Let

Radius of Earth r=6380km

Gravity g=9.8m/s^2

Generally the equation for Gravity at altitude is mathematically given by

 g_s=9.8(\frac{6380}{6380+6.33})^2

 g_s=9.781m/s^2

Therefore

Weight at sea level

 W_s=9.8*85.9

 W_s=841.82N

Weight at 6.33 altitude

 W_a=9.781*85.9

 W_a=840.2N

Therefore

 Weight loss=W_s-W_b

 Weight loss=841.82-840.2

 Weight loss=1.6321N

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A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee
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Electric fields are vector quantities whose magnitudes are measured in units of volts/meter (V/m). Find the resultant electric f
musickatia [10]

Answer:

Er = 231.76 V/m, 27.23° to the left of E1

Explanation:

To find the resultant electric field, you can use the component method. Where you add the respective x-component and y-component of each vector:

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E_1_x = 0V/m\\E_1_y=100V/m

E2:

Keep in mind that the x component of electric field E2 is directed to the left.

E_2_x= 150V/m*-sin(45) = 106.07 V/m\\E_2_y=150V/m*cos(45) = 106.07V/m

∑x: E_1_x+E_2_x = 0V/m - 106.07V/m = -106.07V/m

∑y: E_1_y + E_2_y = 100V/m + 106.07V/m = 206.07V/m

The magnitud of the resulting electric field can be found using pythagorean theorem. For the direction, we will use trigonometry.

||E_r||= \sqrt{(-106.07V/m)^2+(206.07V/m)^2} = 231.76 V/m\\\\\alpha = arctan(\frac{206.7 V/m}{-106.07 V/m}) = 117.24degrees

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3 years ago
Scientists study how the continents move. Why might scientists use a model
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Answer:

B. It is too slow to observe directly

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They move too slow to be able to observe how they move.


I hope it helps! Have a great day!
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