Question

By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect the earth's rotational effects

Answer 1

Answer:

$Weight\ loss=1.6321N$

Explanation:

From the question we are told that:

Weight $W=85.9kg$

Altitude $h= 6.33 km$

Let

Radius of Earth $r=6380km$

Gravity $g=9.8m/s^2$

Generally the equation for Gravity at altitude is mathematically given by

 $g_s=9.8(\frac{6380}{6380+6.33})^2$

 $g_s=9.781m/s^2$

Therefore

Weight at sea level

 $W_s=9.8*85.9$

 $W_s=841.82N$

Weight at 6.33 altitude

 $W_a=9.781*85.9$

 $W_a=840.2N$

Therefore

 $Weight loss=W_s-W_b$

 $Weight loss=841.82-840.2$

 $Weight loss=1.6321N$