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just olya [345]
3 years ago
5

Ralph sold brownies for $0.99 a piece in order to earn money for baseball cards. If the cards cost $1.35 per pack, and if Ralph

had no money left over after buying them, what is the least number of brownies he must have sold
Mathematics
1 answer:
elixir [45]3 years ago
3 0
Least common multiple of 0.99 and 1.35 
99 = 3 x 3 x 11
135 = 3 x 3 x 3 x 5

LCM = 3 x 3 x 3 x 5 x 11 = 1485.
Thus LCM of 0.99 and 1.35 = 14.85

Therefore, the least number of brownies he must have sold = 14.85/0.99 = 15.
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Step-by-step explanation:

|•-•|

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Hope this helps. :)

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professor190 [17]

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Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

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We know three of the roots of the degree-5 polynomial are:

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Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

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