Answer:
1. 4n+2
2. 2n+2
3. 5n-3
4. 4n+1
5. 3n
That's all I can work out I'm sorry
B since a circle is all the points equidistant to a given point called the center of the circle.
Answer:
the answer is 2 + i.
Step-by-step explanation:
Let the square root of 3 + 4i be x + iy.
So (x + iy) (x +iy) = 3 +4i
=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i
=> x^2 – y^2 + 2xyi = 3 + 4i
Equate the real and complex terms
=> x^2 - y^2 = 3 and 2xy = 4
2xy = 4
=> xy = 2
=> x = 2/y
Substitute in
=> x^2 - y^2 = 3
=> 4/y^2 - y^2 = 3
=> 4 – y^4 = 3y^2
=> y^4 + 3y^2 – 4 = 0
=> y^4 + 4y^2 – y^2 – 4 =0
=> y^2(y^2 + 4) – 1(y^2 + 4) =0
=> (y^2 – 1) (y^2 + 4) =0
Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.
Therefore y = 1 and x = 2/1 = 2
The required square root of 3 + 4i is 2 + i.
9514 1404 393
Answer:
(i) ∠CDF = 86°
(ii) ∠BAD = 141°
Step-by-step explanation:
(i) Angles CDF and GFD are "alternate interior" angles, so are congruent.
∠CDF = 86°
__
(ii) Angles BAD and CDA are "alternate interior angles, so are congruent. Angle CDA is the sum of angles CDH and HDA. Angle CDH is supplementary to angle CDF, so is ...
∠CDH = 180° -∠CDF = 180° -86° = 94°
Then ...
∠CDA = ∠CDH +∠HDA = 94° +47°
∠CDA = 141°
