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trasher [3.6K]
3 years ago
14

What are four different ways of representing functions? How can you tell if a relationship is a function?

Mathematics
1 answer:
Nady [450]3 years ago
5 0
It’s on the internet
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Please help me it’s due today at 4:20pm please help me please please help me
Sergio039 [100]

Answer:

x = 3, the error is that the -2x should be added.

Step-by-step explanation:

The -2x should be added to the left side.

3x - 7 = -2x + 8

3x + 2x = 8 + 7

5x = 15

x =3

Answer lest edited 3:11 PM Central, 11/24/2020

4 0
3 years ago
Read 2 more answers
Which two-dimensional figure results from slicing the sphere with the blue plane?
alexgriva [62]
The answer is A parabola
8 0
3 years ago
The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

#SPJ4

3 0
2 years ago
In previous months, you ordered 80 boxes of pens per month. This month, you want to decrease the number of boxes of pens you ord
Lapatulllka [165]
80(0.40)=32
80-32=48 boxes of pens
3 0
3 years ago
Read 2 more answers
the lenghty of a rectangal is 8 feet more than its width. the pirimete of the rectangle is 72 feet. Find the width
morpeh [17]

Width of the rectangle is 14 ft

Step-by-step explanation:

  • Step 1: Let the width of the rectangle be x. Then length = 8 + x. Perimeter = 72 ft.

Perimeter = 2(length + width)

72 = 2 (8 + x + x)

72 = 16 + 4x

4x = 56

x = 56/4 = 14

∴ Width of the rectangle is 14 ft

3 0
3 years ago
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