What are four different ways of representing functions? How can you tell if a relationship is a function?

Mathematics

1 answer:

Nady [450]2 years ago

5 0

It’s on the internet

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Find the volume of the figure shown 2m 6m 6m 9m 16m

navik [9.2K]

Answer:

the answer is 10368 hope this help have a great day mark brainliest pls

Step-by-step explanation:

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2 years ago

What’s distributive property to express 36+16

Gennadij [26K]

Factors of 36 are 18,12,9,6,4,3,2,1

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2 years ago

What are the possible values of x in 8x2 + 4x = -1?

Westkost [7]

Answer:

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

Step-by-step explanation:

$8x^2+4x+1=0$

Using Quadratic formula to solve this equation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}$

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

4 0

2 years ago

PLLZZZZZZZ HELP!!!!!

Gnoma [55]

The answer is 8 and heres why:

$64^{\frac{3}{6}} \\\frac{3}{6}=\frac{1}{2} \\ \\64^{\frac{1}{2}} \\ \\\mathrm{Factor\:the\:number:\:}\:64=8^2 \\\left(8^2\right)^{\frac{1}{2}} \\ \\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} \\\left(8^2\right)^{\frac{1}{2}}=8^{2\cdot \frac{1}{2}}=8$