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zvonat [6]
3 years ago
9

Select the correct answer from each drop-down menu.Shape I is similar to shape II.​

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

The first one is Translation 3 units down and8 units left, then a dialationby a scale factor of 2

Step-by-step explanation:

SIZIF [17.4K]3 years ago
3 0

Answer:

Translation (moving the figure) will map figure 1 onto figure 2 and then after this , dilation by a scale factor of "2"

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Two sides of a triangular tile measure 4 inches and 6 inches. The length of the third side is either 7 inches or 10 inches. Whic
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I think it would be 10 in
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3 years ago
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I NEED HELP WITH QUESTION PLEASE!!<br> What is the inverse of f(x)<br> (x) = (x-4)² for x ≥ 4?
goblinko [34]

Answer:

4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Step-by-step explanation:

<u>Definition of the inverse of a function</u>

A function g is the inverse of a function f if whenever y=f(x) then x=g(y). In other words, applying f and then g is the same thing as doing nothing. We can write this in terms of the composition of f and g as g(f(x))=x. The domain of f becomes the range of g and the range of f becomes the domain of g

To solve for the inverse of the function f(x) =\left(x-4\right)^2

Let y=\left(x-4\right)^2

\mathrm{Replace}\:x\:\mathrm{with}\:y \text{ and replace }\:y\:\mathrm{with}\:x

x=\left(y-4\right)^2

Switch sides
\left(y-4\right)^2=x

Take square roots on both sides
y-4=\pm\sqrt{x}

Add 4 on both sides to solve for y

y = \pm\sqrt{x} + 4

We have two solutions

y=\sqrt{x}+4,\:y=-\sqrt{x}+4

To determine which one of these to be chosen not that in the given choices we can eliminate the first two since x cannot be negative

The third choice can also be eliminated since
-\sqrt{x} + 4 is a decreasing function for x \ge 0

So the last answer choice is correct and the inverse off(x) = (x-4)^2

is given by  f^{-1}(x) = \sqrt{x} + 4

Answer:4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Note

Domain of  (x-4)² is [4, ∞) since x ≥ 4 and (x-4)²  cannot be negative

Range of (x-4)²  is [0,  ∞)

Domain of \sqrt{x}\:+\:4 is [0, ∞)

Range of \sqrt{x}\:+\:4 is [4, ∞)

so indeed the domain of (x-4)² has become the range of \sqrt{x}\:+\:4 and the range of (x-4)² has become the domain of \sqrt{x}\:+\:4

5 0
1 year ago
Which attribute is NOT always true for a rhombus?
yaroslaw [1]

Answer:

the answer would be b)

Step-by-step explanation:

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3 years ago
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An HVAC tech needs to figure out the size of a room to put in the correct size air duct. The room is 11.5 feet wide, 13 feet lon
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Answer:

answer d

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1,196 ft³

put 50point pls

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C.) is the correct answer! I’m 100% sure!

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