Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
<span> x - 4y = -5
-x + 6y = 7
---------------add
2y = 2
y = 1
</span> x - 4y = -5
x - 4(1) = -5
x - 4 = -5
x = -1
answer
x = -1 and y = 1
Answer:
oh nah oh yea oh nah the answer is this the answer is that
Step-by-step explanation:
Answer:
a=11
Step-by-step explanation:
a=m2 +2
a= (-3)2+2
a=9+2
a=11