Answer:
D. Newton's Third Law of Motion
Explanation:
Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out
Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.
Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.
Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )
I hope this helps!
Answer:
(a): 
(b): 
Explanation:
<u>Given:</u>
- Charge on one sphere,

- Charge on second sphere,

- Separation between the spheres,

Part (a):
According to Coulomb's law, the magnitude of the electrostatic force of interaction between two static point charges is given by

where,
k is called the Coulomb's constant, whose value is 
From Newton's third law of motion, both the spheres experience same force.
Therefore, the magnitude of the force that each sphere experiences is given by

The negative sign shows that the force is attractive in nature.
Part (b):
The spheres are identical in size. When the spheres are brought in contact with each other then the charge on both the spheres redistributes in such a way that the net charge on both the spheres distributed equally on both.
Total charge on both the spheres, 
The new charges on both the spheres are equal and given by

The magnitude of the force that each sphere now experiences is given by
- R=ρ×L/A
ρ=R×A/L
A=pie(r²)=pie(0.6²)=pie(0.36)=1.13
ρ=2ohm×1.13mm²/1500mm
ρ=0.0015ohm.mm
2. we were told that the wires were made of the same substance so the resistivity(ρ)is the same for both wires so:
R=ρ×L/A
R=0.0015ohm.mm×500mm/0.09mm²
R=8.3'ohm
so our resistance for the second wire is :
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>R</em><em>=</em><em>8</em><em>.</em><em>3</em><em>'</em><em>ohm</em>