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bezimeni [28]
3 years ago
5

PLEASE HELP MEE PLEASE!​

Physics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

<h3>Answer C. grams</h3>

Explanation:

I hope you like it

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What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity
egoroff_w [7]

Answer:

The force exerted on a moving charge is 1.02\times 10^{-3}\ N.                

Explanation:

We have,

Charge, q=-2\ \mu C

Magnetic field, B=3\times 10^{-4}\ T

Velocity of charged particle, v=5\times 10^6\ m/s

Angle through the magnetic field, \theta=20^{\circ}

It is required to find the force exerted on a moving charge. Due to the motion in charge, magnetic force acts on it. It can be given by :

F=qvB\sin\theta

Plugging all values above

F=-2\times 10^{-6}\times 5\times 10^6\times 3\times 10^{-4}\times \sin (20)\\\\F=1.02\times 10^{-3}\ N

So, force exerted on a moving charge is 1.02\times 10^{-3}\ N.

4 0
3 years ago
A large bottle contains 150 L of water, and is open to the atmosphere. If the bottle has a flat bottom with an area of 2 ft, cal
Yuri [45]

Answer:

Total pressure exerted at bottom =  119785.71 N/m^2

Explanation:

given data:

volume of water in bottle = 150 L = 0.35 m^3

Area of bottle = 2 ft^2

density of water = 1000 kg/m

Absolute pressure on bottom of bottle will be sum of atmospheric pressure and pressure due to water

Pressure due to water P = F/A

F, force exerted by water = mg

m, mass of water = density * volume

                             =  1000*0.350 = 350 kg

F  = 350*9.8 = 3430 N

A = 2 ft^2 = 0.1858 m^2  

so, pressure P = 3430/ 0.1858 = 18460.71 N/m^2

Atmospheric pressure

At sea level atmospheric pressure is 101325 Pa

Total pressure exerted at bottom  = 18460.71 + 101325 = 119785.71 N/m^2

Total pressure exerted at bottom =  119785.71 N/m^2

6 0
4 years ago
If 68 Joules were necessary to move a crate with 4N of force applied, how far was the crate moved
Feliz [49]

Answer:

17 m

Explanation:

Work done is the product of force and perpendicular distance moved, therefore, expressed as

W=Fd

Where F represent the applied force, d is perpendicular distance and W is work done.

Making d the subject of the formula then

d=\frac {W}{F}

Substituting 68 J for work and 4 N for force then

d=\frac {68}{4}=17 m

Therefore, the distance is equivalent to 17 m

8 0
4 years ago
the small wobble in the orbit of Neptune helped astronomers discover Pluto. this suggests that this wobble was MOST LIKELY cause
anyanavicka [17]
Most likely gravity, because the gravity would pull it off course or wobble.
3 0
4 years ago
Read 2 more answers
A bat hits a moving baseball. If the bat delivers a net eastward impulse of 0.80 N-s and the ball starts with an initial horizon
AURORKA [14]

Answer:

0.084 kg

Explanation:

I = 0.80 N-s (East wards) = 0.80 i N-s

u = 3.8 m/s = - 3.8 i m/s

v = 5.7 m/s = 5.7 i m/s

Let m be the mass of bat.

I = m (v - u)

0.8 i = m ( 5.7 i + 3.8 i)

0.8 i = m x 9.5 i

m = 0.084 kg

8 0
3 years ago
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