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3 years ago

When an atom that has no charge loses two electrons, it becomes a

Physics

1 answer:

kicyunya [14]3 years ago

3 0

Answer:

positive ion

Explanation:

due to the fact it loses electrons there is 2 more protons than electrons

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A bicycle of mass m requires 50 J of work to move from rest to a final speed v. If the same amount of work is performed during t

insens350 [35]

Answer:

The final speed of the second bicycle is (v·√2)/2

Explanation:

The mass of the given bicycle = m

The amount of work required to move the bicycle from rest to speed v = 50 J

The final speed of the first bicycle = v

The mass of the second bicycle = 2m

Therefore, from conservation of energy, we have;

Work required by the first bicycle = Kinetic energy gained by the bicycle

The kinetic energy = 1/2·m·v²

∴ Energy required by the first bicycle = 50 J = 1/2·m·v²

Given that the same amount of work is performed on the second bicycle, we have;

Work performed on the second bicycle = 50 J = kinetic energy of second bicycle = 1/2·(2·m)·v₂²

Also, given that 50 J = 1/2·m·v², we have;

Work performed on the second bicycle = 50 J = 1/2·m·v²= 1/2·(2·m)·v₂²

1/2·m·v²= 1/2·(2·m)·v₂²

m·v² = 2·m·v₂²

v² = 2·v₂²

v₂ = √(v²/2) = v/√2 = (v·√2)/2

v₂ = (v·√2)/2

The final speed of the second bicycle = v₂ = (v·√2)/2.

3 0

3 years ago

A tuning fork is held over a resonance tube, and resonance occurs when the surface of the water is 12 cm below the top of the tu

Rainbow [258]

Answer:

786 Hz

Explanation:

Recall, the speed of sound is

v = 332 + 0.6t

Where t = 23°

v = 332 + 0.6(23)

v = 332 + 13.8

v = 345.8 m

Also, it is known that distance between two consecutive resonance length is half of the wavelength.

L2 - L1 = λ/2

34 - 12 = λ/2

λ/2 = 22

λ = 44 cm

Finally, remember that also

Frequency = speed/ wavelength

Frequency = 345.8/0.4

Frequency = 786 Hz

Therefore, the frequency of the tuning fork is 786 Hz

6 0

3 years ago

Estimate the theoretical fracture strength of a brittle material if it is known that fracture occurs by the propagation of an el

julia-pushkina [17]

The solution as per the attached photo.

4 0

4 years ago

If given both the speed of light in a material and an incident angle. How can you find the refracted angle?

Basile [38]

Answer:

$r = Sin^{-1}\left ( \frac{v Sini}{c} \right )$

Explanation:

Let the speed of light in vacuum is c and the speed of light in medium is v. Let the angle of incidence is i.

By using the definition of refractive index

refractive index of the medium is given by

n = speed of light in vacuum / speed of light in medium

n = c / v ..... (1)

Use Snell's law

n = Sin i / Sin r

Where, r be the angle of refraction

From equation (1)

c / v = Sin i / Sin r

Sin r = v Sin i / c

$r = Sin^{-1}\left ( \frac{v Sini}{c} \right )$

8 0

4 years ago

Briefly describe the layers of the earth.

Strike441 [17]

<span>Crust: The thin, outer layer of the earth. Less than 1% of the Earth's mass.Made of solid rock, broken into plates.

Mantle: Molten rock on which plates float. Contains 67% of the earth's mass.
<span>
Core: Inner layer of the Earth. Made of both solid and liquid metals.</span></span>

7 0

3 years ago