3 years ago

Please help! giving BRAINLIEST

Mathematics

1 answer:

Stolb23 [73]3 years ago

7 0

I think A would be your best answer or C because of the down hill slope. Also I would check with your teacher

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Using addition formula solve tan 15

salantis [7]

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2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

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tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

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Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

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3 years ago

Please help! giving BRAINLIEST​

Please help! giving BRAINLIEST