Question

How do you solve this geometry problem

Answer 1

From the Figure We can Notice that :

Opposite Side - AB = 1

Adjacent Side - OB = $\sqrt{3}$

We know that :

$Tan\theta = \frac{Opposite\:Side}{Adjacent\:Side}$

$\implies Tan\theta = \frac{1}{\sqrt{3}}$

⇒ θ = 30°

We know that :

$Sin\theta = \frac{Opposite Side}{Hypotenuse}$

⇒ $Sin30 = \frac{1}{AO}$

⇒ $\frac{1}{2} = \frac{1}{AO}$

⇒ AO = 2