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3 years ago

10

I’ll mark Brainly! Andy deposits $25 in his checking account.

2 answers:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

1. $25

2. 12

3. -12

4. -12

5. -25

Step-by-step explanation:

miskamm [114]3 years ago

4 0

1. Alright so the first one is Andy DEPOSITS money that means he adds money so that is a positive 25.

2. second one it says bay city is 12 ft ABOVE sea level that is also a positive number so that is positive 12.

3. For the third one a team LOST 12 yards so that is negative

4. The temperature is 12 degrees BELOW zero so that means it’s a negative 12

5.Anna WITHDREW $25 form a atm so that means she took out with is a negative 25

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Write the equation of a line that has a slope of 1/2 and passes through (6, -4). Write your answer in slope-intercept form. PLEA

Tems11 [23]

Answer:

y = 1/2x - 7

Step-by-step explanation:

y = 1/2x + b

-4 = 1/2(6) + b

-4 = 3 + b

-7 = b

8 0

2 years ago

1. $17.04 for 4 packages

yan [13]

answer

they are each $4.26

5 0

3 years ago

VLD [36.1K]

Answer:

10

Step-by-step explanation:

Let c = sum of ages of all children.

mean age of all children = c/15 = 7

c = 15 * 7 = 105

The sum of the ages of all children is 105.

Let b = sum of ages of the 9 boys.

mean age of boys = b/9 = 5

b = 9 * 5 = 45

The sum of the ages of the boys is 45.

The sum of the ages of the girls is c - b.

c - b = 105 - 45 = 60

The number of girls is 15 - 9 = 6

mean age of girls = (sum of ages of the girls)/(number of girls) =

= 60/6 = 10

3 0

3 years ago

PLEASE HELP!!!!!!!!!!

yan [13]

$115 = l \times 2.5 \times 5.75$

$\huge \mathrm{Answer࿐}$

given :

$\longmapsto$ volume = 115 yd³

Dimensions are :

$2\frac{1}{2} yd$

$5\frac{3}{4} yd$

L

We know,

$\large \boxed{ \mathrm{volume = l \times b \times h}}$

$115 = 2\frac{1}{2} \times 5\frac{3}{4} \times l$

$l \times \dfrac{5}{2} \times \dfrac{23}{4} = 115$

$l \times \dfrac{115}{8} = 115$

$l = 115 \times \dfrac{8}{115}$

$l = 8 \: yd$

Therefore Length of the prism is 8 yards.

_____________________________

$\mathrm{ \#TeeNForeveR}$

5 0

3 years ago

30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

2 years ago