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2 years ago

Please help giving brainlist

Mathematics

2 answers:

kodGreya [7K]2 years ago

5 0

That’s what she said

mrs_skeptik [129]2 years ago

4 0

-2 " -1,5 : -3-2 " -4/3 " -1 " 0 " 1 " 3/2 " 2
hv ju huy

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Please answer!! will give brainliest!

ella [17]

Answer:

average mean not sure please

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3 years ago

Which of the following shows the reflection?

AysviL [449]

iii shows the reflection

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2 years ago

Read 2 more answers

An object is acted upon by the forces F1=<10,6,4> and F2=<0,3,9>. Find the force F3 that must act on the object

murzikaleks [220]

$\vec F_3=\langle x,y,z\rangle$ is a force vector such that

$\vec F_1+\vec F_2+\vec F_3=\vec0$

$\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle$

$\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13$

So the missing force is

$\boxed{\vec F_3=\langle-10,-9,-13\rangle}$

8 0

2 years ago

Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...

timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

$a_1=-36$

now, we can find common ratio

$r=\frac{6}{-36}$

$r=-\frac{1}{6}$

now, we can find nth term

$a_n=a_1(r)^{n-1}$

now, we can plug values

and we get

$a_n=36(-\frac{1}{6})^{n-1}$

now, we can find 5th term , 6th term, 7th term

fifth term:

$a_5=36(-\frac{1}{6})^{4}$

$a_5=\frac{1}{36}$

sixth term:

$a_6=36(-\frac{1}{6})^{5}$

$a_6=-\frac{1}{216}$

seventh term:

$a_7=36(-\frac{1}{6})^{6}$

$a_7=\frac{1}{1296}$

so, next terms are

$a_5=\frac{1}{36}$ , $a_6=-\frac{1}{216}$

, $a_7=\frac{1}{1296}$ .............Answer

6 0

3 years ago

7 Chris needs to cut a roll of twine into 16 equal lengths for a

jeka57 [31]

Answer:

I am pretty sure it is 56 because all you have to do is dvided and it comes out to 56.25 but you cant have .25 because that is not an equal peice so yeah I think it is 56

8 0

2 years ago