Please help giving brainlist

Mathematics

2 answers:

kodGreya [7K]3 years ago

5 0

That’s what she said

mrs_skeptik [129]3 years ago

4 0

-2 " -1,5 : -3-2 " -4/3 " -1 " 0 " 1 " 3/2 " 2
hv ju huy

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goblinko [34]

Answer:

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NEED HELP FAST PLEASE Evaluate the limit. a.4 c.1 b.2 d.limit does not exist

BlackZzzverrR [31]

We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
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Evaluating again for n = inf:
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4 years ago

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How do I make 2 3/4 into a decimal?

klasskru [66]

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4 years ago

Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane

Vinil7 [7]

I'm thinking this is what the problem looks like: $\frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}$ . The first thing to do is to move the $\frac{x}{x-4}$ over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this: $\frac{4-x}{x-4}= -\frac{4}{3}$ . The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.

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3 years ago