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3 years ago

12

Help Meh PleAse

2 answers:

Solnce55 [7]3 years ago

8 0

Convex = Irregular
Concave = Regular

This has 6 sides, so it's a hexagon.

Therefore it's a convex hexagon.

neonofarm [45]3 years ago

5 0

We can use the elimination process in this one..

The polygon has 6 sides so it's a hexagon. Which means it's not A or D.

Convex lens are narrower from the middle and concave is thicker from the middle.. Which means it's not concave and not B either.

It's C. <span>convex hexagon</span>

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A regular polygon is inscribed in a circle of radius 11 cm. Calculate the perimeter of the polygon to the nearest tenth if the p

Oduvanchick [21]

I believe the answer is 176cm cause if the radius is 11 the diameter is 22 so I hope this helps!

7 0

3 years ago

This question has three parts. Answer the parts in order.

nalin [4]

Answer:

The area of the smallest section is $A_{1}=100yd^{2}$

The area of the largest section is $A_{2}=625yd^{2}$

The area of the remaining section is $A_{3}=250yd^{2}$

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

$A_{1}=10yd*10yd$

$A_{1}=100yd^{2}$

- Area of the second section:

$A_{2}=x^{2}$ (Eq.1)

- Area of the third section:

$A_{3}=width*length$

$A_{3}=10yd*x$ (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

$A_{1}+A_{2}+A_{3}=975yd^{2}$

Replacing values:

$100+x^{2}+10x=975$

Solving for x:

$x^{2}+10x-875=0$

$x=\frac{-10+\sqrt{100+(4*875)}}{2}$

$x=\frac{-10+\sqrt{3600}}{2}$

$x=\frac{-10+60}{2}$

$x=25$

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

$A_{2}=25^{2}$

$A_{2}=625yd^{2}$

- From Eq.2:

$A_{3}=10*25$

$A_{3}=250yd^{2}$

3 0

3 years ago

The flight path of a plane is a straight line from city J J to city K K. The roads from city J J to city K K take the long way a

Vika [28.1K]

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

4 0

3 years ago

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just olya [345]

60 miles an hour for 45 minutes = 45 miles
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Total =70 miles

7 0

3 years ago

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kondaur [170]

n / 82 is your answer

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