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2 years ago

Use the chemical reaction to answer the question.

Physics

2 answers:

balu736 [363]2 years ago

7 0

Answer:

I believe this answer is -They maintain their properties-

Explanation:

Let's see what others say. :)

daser333 [38]2 years ago

6 0

The answer should be the first one, maintaining their properties

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L'aigua es una mescla de d'oxigen i hidrogen

pshichka [43]

Answer:

Una Mezcla Homogénea es aquella mezcla en la que las sustancias que la forman poseen una combinación uniforme.Son ejemplos de Mezclas Homogéneas: Compuesta

Explanation:

Aire (es una mezcla de gases homogénea formada principalmente por de nitrógeno, oxígeno, vapor de agua, dióxido de carbono...)

Leche (mezcla de agua, carbohidratos, proteínas...)

Bebida alcohólica (mezcla de agua y alcohol etílico)

Acero (mezcla de elementos aleados como el hierro, el carbono y otras sustancias)

Petróleo (mezcla de hidrocarburos)

Agua de mar (mezcla de agua, cloruro sódico y otras sustancias)

Mezcla de agua y sal disuelta

Agua azucarada (mezcla de agua y azúcar)

Aleación metálica (las aleaciones metálicas son mezclas en las que se combinan diferentes metales de una manera homogénea y definida)

Perfume (mezcla de agua y otras sustancias olorosas cuya composición es uniforme)

3 0

3 years ago

What physical quantity is a measure of the amount of inertia an object has?

satela [25.4K]

Mass is the physical quantity

3 0

3 years ago

A +71 nC charge is positioned 1.9 m from a +42 nC charge. What is the magnitude of the electric field at the midpoint of these c

viva [34]

Answer:

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC = $71\times 10^{- 9} C$

Q' = + 42 nC = $42\times 10^{- 9} C$

Separation distance, d = 1.9 m

Solution:

To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

$\vec{E} = \frac{Q}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}$

$\vec{E} = \frac{71\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}$

$\vec{E} = 708.03 N/C$

Now,

Electric field at the mid-point due to charge Q' is given by:

$\vec{E'} = \frac{Q'}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}$

$\vec{E'} = \frac{42\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}$

$\vec{E'} = 418.84 N/C$

Now,

The net Electric field is given by:

$\vec{E_{net}} = \vec{E} - \vec{E'}$

$\vec{E_{net}} = 708.03 - 418.84 = 289.19 N/C$

5 0

2 years ago

Technician A says crimping solderless connections is the best method of splicing wires. Technician B says crimping should not be

algol13

Answer:

Technician b is correct.

Explanation:

Crimping cable allows a firm connection in mechanical terms and allows a low resistance path for the signal or the current flow, solder although it is better in terms of electrical conduction, can be impractical if the cable is subjected to excessive movement.

A crimped cable with excessive movement can also be easily broken at the ends, where it joins the part of the cable that is crimped, for this reason, a cable that is in excessive motion is recomended to be spliced by joining cable with cable .

In order to decide which metod is better for splicing cables its necessary to evaluate each situation separatly.

7 0

3 years ago

If the wavelength of an electromagnetic wave is too long or too short,

Evgesh-ka [11]

it is no longer and electromagnetic wave.

3 0

3 years ago

Read 2 more answers