The rate of altitude increase is equivalent to the vertical component of the pilot's velocity. Let the first pilot's velocity be A and the second's be B.
Ay = Asin(∅)
Ay = 400sin(30)
Ay = 200 mph
By = Bsin(∅)
By = 300sin(40)
By = 192.8 mph
200 - 192.8 = 7.2 mph
The first pilot gains altitude faster by 7.2 mph than the second pilot.
Answer: The ice absorb 6671.1 kJ of thermal energy.
Explanation:
The conversions involved in this process are :
Now we have to calculate the enthalpy change.
where,
= enthalpy change = ?
m = mass of ice = 20.0 kg = 
(1kg=1000g)
n = number of moles of ice= 
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
Now put all the given values in the above expression, we get
(1 kJ = 1000 J)
Therefore, the enthalpy change is, 6671.1 kJ
<span>the dependent variable
<span>a variable (often denoted by y ) whose value depends on that of another.</span>
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