The answer is B, 1/4 of the cake
<span>m1v1 + m2v2 = (m1+m2)*(-vf)
6*5 + 2*v2 = (6 + 2)*(-2)
v2 = -16/2 = -8 m/s i</span>
Answer:
ikd
Explanation:
I don't get what your asking pls make it more clear
The increase in temperature of the metal hammer is 0.028 ⁰C.
The given parameters:
- <em>mass of the metal hammer, m = 1.0 kg</em>
- <em>speed of the hammer, v = 5.0 m/s</em>
- <em>specific heat capacity of iron, 450 J/kg⁰C</em>
The increase in temperature of the metal hammer is calculated as follows;

where;
<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>
<em />
Assuming the metal hammer is iron, c = 450 J/kg⁰C

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.
Learn more about heat capacity here: brainly.com/question/16559442