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vodomira [7]
3 years ago
7

What is the Frequency of a light wave with a Wavelength of 680 x 10^-7m?

Physics
1 answer:
exis [7]3 years ago
3 0

Answer:

5000°A

Explanation:

If it is right answer so please mark me as brainleist anwer as ur wish

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Wittaler [7]
Its c after the meteorite hit earth it created a different environment worldwide that animals weren't able to adapt to due to its harsh conditions 
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3 years ago
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There is a naturally occurring vertical electric field near the Earth’s surface that points toward the ground. In fair weather c
trasher [3.6K]

Answer:

\frac{F}{W} = 9.37 \times 10^{-4}

Explanation:

Radius of the pollen is given as

r = 12.0 \mu m

Volume of the pollen is given as

V = \frac{4}{3}\pi r^3

V = \frac{4}{3}\pi (12\mu m)^3

V = 7.24 \times 10^{-15} m^3

mass of the pollen is given as

m = \rho V

m = 7.24 \times 10^{-12}

so weight of the pollen is given as

W = mg

W = (7.24 \times 10^{-12})(9.81)

W = 7.1 \times 10^{-11}

Now electric force on the pollen is given

F = qE

F = (-0.700\times 10^{-15})(95)

F = 6.65 \times 10^{-14} N

now ratio of electric force and weight is given as

\frac{F}{W} = \frac{6.65 \times 10^{-14}}{7.1 \times 10^{-11}}

\frac{F}{W} = 9.37 \times 10^{-4}

7 0
3 years ago
A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
Which of the following statements about digestion is/are TRUE? (Select all that apply.)
MArishka [77]
1st one and fourth one are true.
7 0
3 years ago
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a gas has a volume of 8 liters at a temperature of 300 K the volume is then increased to 12 Liters what is the new temperature (
natali 33 [55]
300/8 = 37.5
37.5 x 12 = 450
New temp. = 450 K
Hope this helps!
6 0
3 years ago
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