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1 year ago

If an object has a mass of 4 kg and an acceleration of 8 m/s2, what is the force this object exerts?

Physics

1 answer:

Slav-nsk [51]1 year ago

7 0

The force acting on the object will be 32 N.

Newton's second law of motion states that, "the force is equal to the change in momentum per change in the time". The mathematical form of the law is given below.

$F = \frac{dP}{dt}=\frac{d(mv)}{dt}=m\frac{dv}{dt}=ma$

Where P = momentum, t = time, m =mass, v = velocity, a = acceleration and F = force.

The mass of the object is 4 kg and acceleration is 8 m/s^2. Substitute the values in the equation and we will get the force.

F = ma

F = 4 kg * 8 m/s^2

F = 32 kg.m/s^2

F = 32 N

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My name is Ann [436]

Answer: 43.01 m

Explanation:

Given that :

Time ball uses in the air = 5.93, time it takes to reach maximum height and return = time of flight(T) = 5.93 s

TIME of flight (T) = 2 * time taken(t)

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S = 0.5at²

S = maximum height

Tjme taken (t) = time of flight / 2 = 5.93/2 = 2.965 s

Hence,

S = 0.5at²

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2 years ago

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For example, Try dropping a pen and a paper(Vertically) at the same height, you'll see they'll reach the ground at the same time.

If you count wind resistance, the heavier ball will hit the ground faster, because the air molecules will resist the lighter ball compared to the heavier ball.

6 0

3 years ago

A 100 N force is applied to move an object a horizontal distance of 5 meters at constant speed in 10 seconds. How much power is

Tpy6a [65]

Answer:

50 W

Explanation:

<h3><u>Given :</u></h3>

Force applied = 100 N
Distance covered = 5 metres
Time = 10 seconds

Power

<h3><u>Solution :</u></h3>

For calculating power, we first need to know about the work done.

$\bf \boxed{Work = Force \times displacement}$

Now, substituting values in the above formula;

Work = 100 × 5

= 500 Nm or 500 J

We know that,

$\bf \boxed{Power=\dfrac{Work\:done}{Time\: taken}}$

Substituting values in above formula;

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3 years ago

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ch4aika [34]

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Explanation:

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Conserving Energy

energy lost by block =Gain in potential energy in spring

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