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Reil [10]
3 years ago
11

5•10^6 is how many times as large as 5•10^6

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

Answer: 100

Step-by-step explanation:

For any two numbers X and Y, you can figure out how many times larger X is than Y by dividing X by Y . For example , 8 is 4 fine larger than 2 because 8/2=4 5*10^6/5*10^4 = 5/5*10^6/10^4 = 1*10^2 = 100

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Find the distance between the points ( 4, 7) and (-1,2
mihalych1998 [28]

Answer:

7.07 (3 significant figures)

Step-by-step explanation:

the distance between the two points on the x axis is 5 and the distance between the two point son the y axis is 5. thus by using pythagerous theorem you are able to get the hypotenuse which is the distance between the two points which in this case is 7.07 when rounded to 3 significant figures. not sure if im correct but i hope it helps

8 0
3 years ago
Only t circled ones somebody plz help I am gonna get a 0 plz help I will give you brainleist
Vikki [24]

Step-by-step explanation:

1) A number <em>m</em> is at least four

<em>m ≥ 4  ['at least' = ≥ symbol]</em>

<em />

2) 4x  ≤ 20x; x=2

4(2) ≤ 20(2)

8 ≤ 40

[Im not sure if this is a solution or and inequality :/ ]

3)  x < 5

--> On the line, draw the number 0, and the number five. 'x < 5' also means 'x is less that five.' So, draw a dot over the line before 5, and make an arrow going to the left of the page,

<-----------------------------------o   5

<---|---|---|---|---|---|---|---|---|---|---|---|---|---|--->

                          0

Hopefully this helps! :)

4 0
3 years ago
EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi
Valentin [98]

If there is such a scalar function <em>f</em>, then

\dfrac{\partial f}{\partial x}=4y^2

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\dfrac{\partial f}{\partial z}=16ye^{4z}

Integrate both sides of the first equation with respect to <em>x</em> :

f(x,y,z)=4xy^2+g(y,z)

Differentiate both sides with respect to <em>y</em> :

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=4e^{4z}

Integrate both sides with respect to <em>y</em> :

g(y,z)=4ye^{4z}+h(z)

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

f(x,y,z)=4xy^2+4ye^{4z}+h(z)

\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}

\implies\dfrac{\mathrm dh}{\mathrm dz}=0

Integrate both sides with respect to <em>z</em> :

h(z)=C

So we end up with

\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}

7 0
3 years ago
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svlad2 [7]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Contact [7]

Answer:

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