52, i am so sorry this is probably incorrect
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
The correct answer is 3.53
Answer: Is not
Step-by-step explanation:
Answer:
3(6) -1
------------
2(6)+1
Step-by-step explanation:
first find r(6)
r(6) =3(6) -1
= 18 -1
Then find s(6)
s(6) = 2(6)+1
Then divide
r(6)/s(6) = 3(6) -1
------------
2(6)+1
