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RideAnS [48]
3 years ago
12

When solving the equation x/5 - 12 = 10, what is your last step?

Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0

Answer:

A multiply by 5

Step-by-step explanation:

x/5-12=10

x/5=10+12

x/5=22

multiple each side by 5

x=22*5

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The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

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4 0
2 years ago
Which measurement is most accurate to describe the weight of an apple
jarptica [38.1K]

Answer: (BRAINLIEST PLEASE)

120 g.

Step-by-step explanation:

3 0
3 years ago
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Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

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Senior = 25+5+5

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Total = 2+25+3+13+20+2+25+5+5

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Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
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Answer:

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5 0
2 years ago
Quanto é o resultado e como ae resolve a seguinte operação: 1.205 × 32 Me ajudem preciso para hj.
Elenna [48]

Answer:

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Step-by-step explanation:

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