1)Enzyme is a protein. The main material of an enzyme is protein
2)It is easily influenced, by environmental change. Environmental factors include temperature, pH, and inhibitor.
3)It acts as catalyst The enzyme functions in accelerating chemical reaction, but the enzyme itself does not change after the reaction ends.
You would be referring to the <em>plant </em>cell.
Answer:
Chloroplasts may be seen on all six sides of a plant cell, which is a three-dimensional entity with typically moderately rounded corners (not in the centre because a big central vacuole fills a very large part of the volume). Chloroplasts are constantly being rearranged by the cell since they are not set in place. Chloroplasts are typically located close to so-called periclinal cell walls, which are oriented in the same 2D orientation as the leaf surface under low light. Chloroplasts seem to "escape" to the anticlinal walls in bright light. Better light harvesting in low light by exposing every chloroplast to light and photoprotection by mutual shading in strong light are likely the fitness benefits provided by this behavior. In the dark, chloroplasts also gravitate toward the anticlinal walls. Thin leaves of submerged aquatic plants like Elodea can be used as microscope specimens to observe chloroplast motions. One can gauge how much light gets through a leaf in land plants. What I just said concerning the top layer(s) of leaves' "palisade parenchyma cells" is accurate. Most of the chloroplasts are found in these cells. Numerous cells in the spongy parenchyma under the palisade layer lack well marked peri and anticlinal walls.
<h2>
How did plant cells incorporate chloroplasts in their DNA?</h2>
Chloroplasts must reproduce in a manner akin to that of some bacterial species, in which the chloroplast DNA is duplicated first, followed by binary fission of the organelle (a kind of protein band that constricts so that two daughter organelles bud off). As a result of some chloroplast DNA actually being integrated into the plant genome (a process known as endosymbiotic gene transfer), it is now controlled in the nucleus of the plant cell itself.
Answer:
The correct answer is option c. "The apparent value of KM increases with a competitive inhibitor, while it remains unchanged with a noncompetitive inhibitor".
Explanation:
The KM value in an enzymatic reaction is defined as the substrate concentration at which the half of the enzyme molecules are binding with the substrate. A way to distinguish between a competitive and noncompetitive inhibition is that the apparent value of KM increases with a competitive inhibitor, while it remains unchanged with a noncompetitive inhibitor. A competitive inhibitor would make that a higher concentration of substrate is needed, while a noncompetitive inhibitor does not change KM since the inhibitor binds to a site of the enzyme different from the active site.
Answer:
1,250,000 shrimps per m³
Explanation:
Population density refers to how dense an area is per unit area/volume, and it is calculated by dividing the number of individuals in that area (population) by the area/volume of that area. That is;
Population density = population (N)/volume
According to this question, a certain lake has a volume of about 480 m³ that harbors a 600 million of freshwater shrimp. This means that;
Population density of the lake = population of shrimps ÷ volume of lake
Population density = 600,000,000 ÷ 480
Population density = 1,250,000 shrimps per m³
Answer:
(a) Immuno-suppressive drug therapy may be used to promote acceptance of the graft.
(b) Use of antibiotics and interferons in case infection occurs in the body of the recipient when immune system is suppressed because of immuno-suppressive drug therapy.
Explanation:
Immuno-supressive drug therapy involves administration of drugs to restrict inhibition of T cells.
Following drugs may be used in such therapy:
(1) Glucocorticoids and corticosteroids: These drugs are helpful in down regulation of GPCR signaling as a result of which prostaglandins are not synthesized.
(2) Cyclosporin - A: It leads to the blockage of activation of T lymphocytes.
(3) Rapamycin: It leads to the inhibition of cellular translation as a result of which immune cells do not get activated.
