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Sedbober [7]
4 years ago
9

Simple Harmonic Motion: A simple harmonic oscillator oscillates with frequency f when its amplitude is A. If the amplitude is no

w doubled to 2A, what is the new frequency
Physics
1 answer:
kherson [118]4 years ago
7 0

Answer:

The frequency will still remain F

Explanation:

Firstly, we should remember that the frequency of a simple harmonic oscillator doesn't depend on the amplitude. Rather, it depends on the spring constant, k, and the mass of the attached weight, m. This means that the change in amplitude will not lead to a corresponding change in frequency.

the frequency is represented by the formula

f = 1/2π * √(k/m),

where

f = frequency of the oscillator

k = spring constant and

m = mass attached to the spring

From the formula above, we can state that the frequency doesn't depend on the amplitude at all, and as such, the amplitude changing from A to 2A, will effect no change in the frequency F.

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List three things that can affect an objects resistance.
DENIUS [597]

Answer:

The amount of air resistance an object experiences depends on its speed, its cross-sectional area, its shape and the density of the air.

Explanation:

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3 years ago
The monomer used as the building block in polyethylene is? Ethene, ethane, monoethane, amino acids?
LuckyWell [14K]
<span>it's ethene and not an amino acid!!! amino acids form proteins as their polymers. </span>
6 0
4 years ago
A 70.0-kg skier is sliding at 4 m/s when they slide down a 2m high hill. At the bottom of the hill they run into a large 2800 N/
Katarina [22]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • mass of skier, m=70\ kg
  • initial velocity of skier, u=4\ m.s^{-1}
  • height of the hill, h=2\ m
  • spring constant, k=2800\ N.m^{-1}

<u>final velocity of skier before coming in contact of spring:</u>

Using eq. of motion:

v^2=u^2+gh

v^2=4^2+9.8\times 2

v=5.9666\ m.s^{-1}

<u>Now the time taken by the skier to reach down:</u>

v=u+gt

5.9666=4+9.8\ t

t=0.2007\ s

<u>Now we calculate force using Newton's second law:</u>

F=\frac{dp}{dt}

F=\frac{m(v-u)}{t}

F=\frac{70\times(5.9666-4)}{0.2007}

F\approx686\ N

<u>∴Compression in spring before the skier momentarily comes to rest:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{686}{2800}

\Delta x=0.245\ m

\Delta x=245\ mm

4 0
3 years ago
in an exothermic chemical reaction the energy gained by the surroundings must be _______ the energy lost by the reaction
Yuliya22 [10]

Answer:

In an exothermic reaction the energy gained by the surroundings must be <u>equal to</u> the energy lost by the reaction.

Explanation:

Exothermic reactions occur by the loss of energy in the form of heat to the surroundings (apparatus and the system).

The heat gained can be quantitatively analysed and measured  provided no product escapes the system and it is numerically equal to the amount of heat lost by the reaction.

4 0
3 years ago
At what angle do the cars move after the collision?
liubo4ka [24]

Answer:

his results in the final angle after the collision of 37.2 degrees basically what we did there is turn the vector into a right triangle. We use sohcahtoa to solve for the angle. Being.

Explanation:

6 0
2 years ago
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