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2 years ago

Calculate the kinetic energy of a 4kg cat running 5m/s

1 answer:

5 0

Kinetic energy = (1/2) (mass) (speed)²

   = (1/2) x (4 kg) x (5 m/s)²

   = (2 kg) x (25 m²/s²)

   = 50 kg-m²/s² = <em>50 joules

</em>

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Nitrous oxide is the chemical name for “laughing gas.” What are the names and the number of atoms in a molecule of nitrous oxide

Vesnalui [34]

2 nitrogen molecules and 1 oxygen molecule

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2 years ago

You start pushing a suitcase full of clothes in the horizontal direction with a force of 25.0 newtons. The weight of the suitcas

sasho [114]

Answer:

Distance traveled will be 5.6307 m

Explanation:

Time t = 3 sec

We have given force F = 25 N

We know that force is given by F = ma

So ma = 25 -----------eqn 1

Weight is given by W = 196 N

We know that weight is given by W = mg

So mg = 196 -----------------eqn 2

From equation 1 and equation 2 $\frac{a}{g}=\frac{25}{196}$

$a=1.2512m/sec^2$

Initial velocity is given as 0 so u = 0 m/sec

From second equation of motion $s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 1.2512\times 3^2=5.6307m$

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3 years ago

What do microorganisms get from soil? What do microorganisms give to soil?

nikitadnepr [17]

Answer:

Organic matter decomposition serves two functions for the microorganisms, providing energy for growth and suppling carbon for the formation of new cells. ... Dead plant residues and plant nutrients become food for the microbes in the soil

Explanation:

6 0

2 years ago

Determine the normal boiling point of a substance whose vapor pressure is 55.1 mm hg at 35°c and has a δhvap of 32.1 kj/mol.

Novosadov [1.4K]

Answer:

389.78681 K

Explanation:

$P_1$ = Initial pressure = 55.1 mmHg

$P_2$ = Final pressure = 1 atm = 760 mmHg

$T_2$ = Boiling point

$T_1$ = Initial temperature = 35°C

$\Delta H_{vap}$ = Heat of vaporization = 32.1 kJ/mol

From the Clausius-Claperyon equation

$ln\dfrac{P_2}{P_1}=(-\dfrac{\Delta H_{vap}}{R})(\dfrac{1}{T_2}-\dfrac{1}{T_1})\\\Rightarrow \dfrac{1}{T_2}=-ln\dfrac{P_2}{P_1}\dfrac{R}{\Delta H_{vap}}+\dfrac{1}{T_1}\\\Rightarrow \dfrac{1}{T_2}=-ln\dfrac{760}{55.1}\dfrac{8.314}{32.1\times 10^{3}}+\dfrac{1}{273.15+35}\\\Rightarrow T_2=\left(-ln\left(\frac{760}{55.1}\right)\frac{8.314}{32.1\times \:10^3}+\frac{1}{273.15+35}\right)^{-1}\\\Rightarrow T_2=389.78681\ K$

The normal boiling point of the substance is 389.78681 K

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2 years ago

An acceleration in the direction of motion increases speed,and an acceleration opposite to the durection of motion decreases spe

Luden [163]

That's 'centripetal acceleration'. It points toward the center of the circle in which the object is traveling, even if it's only a temporary piece of a circle.

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2 years ago