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Dominik [7]
3 years ago
12

Calculate the kinetic energy of a 4kg cat running 5m/s

Physics
1 answer:
natulia [17]3 years ago
5 0

Kinetic energy  =  (1/2) (mass) (speed)²

                         = (1/2) x (4 kg) x (5 m/s)²

                         =      (2 kg) x (25 m²/s²)

                         =    50 kg-m²/s²  =  <em>50 joules

</em>
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Dafna11 [192]

Answer:

(a). The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

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(c). The time is 0.493\times10^{-7}\ sec.

Explanation:

Given that,

Electric field E=-6.00\times10^{5}i\ N/C

Time = 5.0 sec

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a=\dfrac{-6.00\times10^{5}\times1.6\times10^{-19}}{1.67\times10^{-27}}

a=-5.74\times10^{13}\ m/s62

The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). We need to calculate the initial peed

Using equation of motion

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Put the value into the formula

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(c). We need to calculate the time interval over which the proton comes to rest

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t=\dfrac{u}{a}

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Put the value into the formula

t=\dfrac{2.83\times10^{6}}{5.74\times10^{13}}

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(b). The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). The time is 0.493\times10^{-7}\ sec.

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