1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlada [557]
4 years ago
10

Which of the following statements are true? Check all that apply.

Physics
2 answers:
irinina [24]4 years ago
7 0

Answer:

The correct options are (A), (B) and (C).

Explanation:

(A) The electric field between the plates of a parallel plate capacitor is uniform and is given by :

E=\dfrac{Q}{A\epsilon_0}

Where,

Q is the charge

A is the area of cross section

(B) A capacitor is a device that is used to store electric charges and electric potential energy.

Stored potential energy is given by, U=\dfrac{Q^2}{2C}

Where, Q is the charge and C is the capacitance of the capacitor.

(C) The capacitance of a capacitor depends upon its structure.

C=\dfrac{A\epsilon_0}{d}

A is the area of plate. It determines the structure.

BigorU [14]4 years ago
4 0
<span><u>Answers.</u>
a. The electric field between the plates of a parallel capacitor is uniform
b. A capacitor is a device that stores potential energy and electric charges.
c. The capacitance of a capacitor depends upon its structure.
<u>
Explanation </u>
Capacitor is a device that is used to store electric charge. The capacitance that can be stored in a capacitor depend on area of overlap of the plates, dielectric used and distance between the two plates of a parallel capacitor.
From the choices given in the question the one that applies are:
a. The electric field between the plates of a parallel capacitor is uniform
b. A capacitor is a device that stores potential energy and electric charges.
c. The capacitance of a capacitor depends upon its structure.  
</span>
You might be interested in
Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t
Murrr4er [49]
Can you post a picture of the whole thing please
6 0
3 years ago
An electric dipole having dipole moment of magnitude p is placed in a uniform electric field having magnitude E. What is the mag
Daniel [21]

Answer:

Explanation:

The formula for the potential energy of a dipole placed in an electric field is given by

U = - pE Cos θ

where, θ is the angle between dipole moment and the electric field vector.

For θ = 0°,

initial potential energy, Ui = - pE

For θ = 180°,

final potential energy, Uf = - pE Cos 180 = pE

Change in potential energy

ΔU = Uf - Ui

ΔU = pE - (-pE)

ΔU = 2pE

5 0
4 years ago
A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee
GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

d=v_ot+\frac{1}{2}at^2

Now, we transform the total distance the cat would need to travel:

90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0
2 years ago
the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 2.00×
Alexus [3.1K]

Answer: 0.512 kgm²

Explanation:

Given

Force, F = 2*10^3 N

Angular acceleration, α = 121 rad/s²

Lever arm, r(⊥) = 3.1 cm = 3.1*10^-2 m

τ = r(⊥) * F

Also,

τ = Iα

Using the first equation, we have

τ = r(⊥) * F

τ = 0.031 * 2*10^3

τ = 62 Nm

Now we calculate for the inertia using the second equation

τ = Iα, making I subject of formula, we have

I = τ / α, on substituting, we have

I = 62 / 121

I = 0.512 kgm²

Thus, the moment of inertia of the boxers forearm is 0.512 kgm²

5 0
4 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
Sergeu [11.5K]

Answer:

25

Explanation:

magnitude and (b) direction (as an angle relative to the x axis) of the velocity

5 0
3 years ago
Other questions:
  • 3. A bus accelerates at 25 m/s/s. This allows the bus to speed up from 16 m/s to 172 m/s. How long
    7·1 answer
  • After completing a career search, Patrick has decided that he wants to be a paralegal. Which two skills or abilities are importa
    15·2 answers
  • Is metal denting a physical change
    15·1 answer
  • A power of 100 W is delivered to a certain resistor when the applied voltage is 100 V. Find the resistance. Suppose that the vol
    9·1 answer
  • We run a distance of 1000 m at a speed of 4.3 m/s. Calculate the time elapsed to cover this distance
    5·1 answer
  • Really need help with these three similar physics questions as soon as possible!!!
    11·1 answer
  • Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.) a = 2i − 5j + k
    7·1 answer
  • Question 7
    13·1 answer
  • A rocket sled is tested at "5 g" (5 times the acceleration due to gravity). If the sled starts from rest at position d o = 0.00,
    6·1 answer
  • When a jet plane is cruising at high altitude, the flight attendants have more of a "hill" to climb as they walk forward along t
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!