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lana [24]
3 years ago
13

What is the average value of y=cosx/x^2+x+2 on the closed interval "[-1, 3]"?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0
We have 
<span>y=cos x/(x</span>²+x+2)  <span>on the closed interval [-1, 3]
</span><span>
we know that
</span>The average value of f(x) on the interval [a, b] is given by: 
<span>F(avg) = 1/(b - a) ∫ f(x) dx (from x=a to b). 
(b-a)=(3+1)------> 4
</span>= 1/4 ∫ cos(x)/(x² + x + 2) dx (from x=-1 to 3). 

Note that [cos(x)/(x² + x + 2)] does not have an elementary anti-derivative.
 By approximating techniques: 
1/4 ∫ cos(x)/(x^2 + x + 2) dx (from x=-1 to 3) ≈ 0.182951

the answer is
<span>the average value of y = cos(x)/(x</span>²<span> + x + 2) on [-1, 3] is approximately 0.182951</span>

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logarithms are the inverse of exponents, basically, if you have an example like
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if you put logbase10(1000), you'll get 3.
Anyways, though, to solve the problem make a log with a base of 1.075 in your calculator
log21.25(base 1.075) = t
also, because of rules of change of base (might want to look this up to clarify), you can write this as log(21.25)/log(1.075) = t
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Step-by-step explanation:

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Step-by-step explanation:

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