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3 years ago

i have the same hundreds digits as ones. the value of my tens digit is 50. The value of my ones digit is four. the 3 digits are

1 answer:

6 0

454

check...
same hundreds digit as ones : correct
value of tens digit is 50 : correct
value of ones digit is 4 : correct

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Solve for x the rest of the question is in the png

zvonat [6]

Answer:

33.18

Step-by-step explanation:

Use law of sines.

x / sin(65°) = 21 / sin(35°)

x = 21 sin(65°) / sin(35°)

x ≈ 33.18

3 0

3 years ago

Solve x2 − 12x + 5 = 0 using the completing-the-square method. x = six plus or minus the square root of five x = negative six pl

Andru [333]

we are given

$x^2-12x+5=0$

we have to solve it by completing square method

step-1: Move 5 on right side

$x^2-12x+5-5=0-5$

$x^2-12x=-5$

step-2: Break middle term

$x^2-2*6*x=-5$

step-3: Add 6^2 both sides

$x^2-2*6*x+(6)^2=-5+(6)^2$

$(x-6)^2=31$

step-3: Solve for x

$\sqrt{(x-6)^2} =\sqrt{31}$

we wil get two values

First value is

$x-6=\sqrt{31}$

add both sides 6

$x-6+6=6+\sqrt{31}$

$x=6+\sqrt{31}$

Second value is

$x-6=-\sqrt{31}$

add both sides 6

$x-6+6=6-\sqrt{31}$

$x=6-\sqrt{31}$

so, solutions are

$x=6+\sqrt{31}$

$x=6-\sqrt{31}$ .............Answer

5 0

3 years ago

In Diagram 6, JCK is a tangent to the circle ABC

Igoryamba

Answer:

Step-by-step explanation:

if you don't know it choose C

5 0

2 years ago

I feel like this is the same thing from my last question (about how to find arc and angle lengths) but it looks very different.

Gnesinka [82]

Yes it is the same except there are two arcs you need to find the length for in this one.

7 0

3 years ago

The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l

Burka [1]

Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N

5 0

3 years ago