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Strike441 [17]
3 years ago
14

Convert the time. Enter your answer in the box. 4 minutes 53 seconds = seconds

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0
293 seconds ____________
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The Fruitz fruit and vegetable shop is selling grapes at a price which is 10% cheaper than the Happy Fruiterer fruit and vegetab
sdas [7]

Answer:

(a) It costs $55 at Happy Fruiterer

(b) It will cost $49.64

(c) It is cheaper at Happy Fruiterer the second week

Step-by-step explanation:

Since Fruitz shop sells as 10% less than Happy Fruiterer at $50

10% more of $50 = 50 × 10/100 + 50

= $5 + $50 = $55

(a) n Kg of grapes will cost $55 at Happy Fruiterer

(b) if Happy Fruits discounts $55 by 5%, we will have

55 × 5/100 = 2.75

that is $55 - $2.75 = $52.25

If it is discounted further at 5% more the following week, we will have

$52.25 × 5/100 = $2.6125

≈ $2.61

Then the new price for the 2nd week is $52.25 - $2.61

= $49.64

(c) at the second wee of discounting, Fruitz shop still sells at $50 will Happy Fruiterer now see at $49.64. Therefore, it is cheaper at Happy Fruiterer

8 0
3 years ago
I need answer for question 13
Mademuasel [1]

730/27 or improper fractions 27 1/27

6 0
3 years ago
National Ave gas prices
Musya8 [376]
Question: What equation models the data?
For this question I used a software to calculate the equation. When plotted, we can notice that the points form a parabolic function therefore we needed quadratic regression for this one. The quadratic equation is in the form of y=A+Bx+Cx^{2} where y represents the gas prices, x is the year, and A, B, and C are coefficients. I have found A, B, and C using the software and the equation for the data is:

y=-0.092+0.587x-0.026x^{2}

Question: What are the domain and range of the equation?
To find the range of the equation, we just transform the quadratic equation into the form y=a(x-h)^{2}+k. The value for k would be the maximum element in our range, and for the sake of the problem, let's assume that we don't have negative prices.

y=-0.092+0.587x-0.026x^{2}
y+0.092=0.587x-0.026x^{2}
y+0.092=-0.026(x^{2}-22.577x)
y+0.092-0.026(127.442)=-0.026(x^{2}-22.577x+127.442)
y-3.221=-0.026(x-11.289)^{2}
y=-0.026(x-11.289)^{2}+3.221

We can see that 3.221 is the maximum value of the range while zero is the minimum. Thus, we can express the range as {y|0 \leq y \leq 3.221}

For the domain, the number of years can extend infinitely but it will also depend if we want to consider the years where the price will be negative. Thus, let's just find the year when the price would be zero.

0=-0.026(x-11.289)^{2}+3.221
-3.221=-0.026(x-11.289)^{2}
123.885=(x-11.289)^{2}
+-11.130=x-11.289

x=0.159
x=22.419

Anywhere before and after the range of the x values above would result to a negative price therefore we can restrict the domain to those values. However, since x represents the year, we would need to round up the first value and round down the larger value.

Domain: {x|01 \leq x \leq 22}

Question: Do you think your equation is a good fit for the data?
To know whether our equation is a good fit or not, we just look at the value of the correlation coefficient r. We can calculate this manually but in this case I just used a software. According to the software, the value for r is 0.661. This is almost close to a strong correlation which is 0.7 thus we can say that this equation is a good fit.

Question: Is there a trend in the data?
There might be a trend, but it won't be a simple linear one. Since the data initially rose before continuously decreasing, our data would best be described by a quadratic trend. The quadratic trend would be the parabolic equation we just used to model the data.

Question: Does there seem to be a positive correlation, a negative correlation, or neither?
Neither. A positive or negative correlation only applies when we are talking about linear trends, where it's either one variable increases as the other one also increases or the variable decreases as the other one increases. In our case, the price rose and fall as the years increase so there is neither a positive nor a negative correlation.

Question: How much do you expect gas to cost in 2020?
We can answer this question by using the equation that we used to model the data. For this question, we would just need to substitute 20 for x since we want to know the price in 2020 (we have only used the last two digits of the year for the equation) while the answer to this would be the expected price.

y=-0.092+0.587(20)-0.026(20)^{2}
y=-0.092+11.740-10.400
y=1.248

The expected price in 2020 would be 1.248 units.
4 0
3 years ago
On average, a commercial airplane burns about 3.9 × 10³ mL of gasoline per second. There can be as many as 5.1 × 10³ airplanes i
algol13
We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes. 

Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes

We calculate as follows:

</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
8 0
4 years ago
Read 2 more answers
Classify the equation 64x - 16 = 16(4x - 1) as
Maksim231197 [3]

Answer:

there is no solution 64x-16=64x-16

Step-by-step explanation:

if you distrubute then you will see the numbers are the same on both sides

7 0
3 years ago
Read 2 more answers
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