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laila [671]
4 years ago
7

Find the distance between -2 1/2 and -5 3/4 on a number line

Mathematics
1 answer:
Elena-2011 [213]4 years ago
5 0

Answer:

13/4

Step-by-step explanation:

Convert these numbers to a mixed fraction.

-5 3/4 => -23/4

-2 1/2 => -5/2

Make them have a common denominator

-5/2 => -10/4

-23/4 can stay the same.

To find the distance between the two numbers, subtract the lesser value from the greater value.

-23/4 is <u>less</u> than -10/4.

(-10 - (-23)) /4

= 13/4

Therefore the distance between -2 1/2 and -5 3/4 on a number line is 13/4.

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A pack of 100 wolves on a remote island are suffering from a new disease. Let W(t) be the number of sick wolves at time t. Suppo
Olin [163]

Answer:

b)\,\frac{dW}{dt}=kt\sqrt{W}, \,W(0)=10

Step-by-step explanation:

Initial number of sick wolves = W(0) = 10

At time t, no. of sick wolves = W(t)

Given that disease is spreading at a rate proportional to the product of the time elapsed and the square root of the number of sick wolves:

\frac{dW}{dt}=kt\sqrt{W}

Mathematical model of above case is:

\frac{dW}{dt}=kt\sqrt{W}, \,W(0)=10

5 0
3 years ago
Write the fraction as the sum of two fractions with the same denominator
grandymaker [24]
1/4 + 1/4 = 1/2

I got 1/2 because if you add 1/4 and 1/4 you'd get 2/4, and when you simplify 2/4 you'd get 1/2.
3 0
4 years ago
Compute 860 times 500
mr_godi [17]

Answer:430,000

Step-by-step explanation:

Type it into your calculator and you get that number

8 0
3 years ago
Determine the sign of cos pi/3 without using a calculator.
andre [41]
Pi/3 is in the first quadrant, and all trigonometric functions are positive in the first quadrant,
Therefore, cos pi/3 is positive.

8 0
3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0
2 years ago
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