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Tju [1.3M]
2 years ago
15

Which algebraic expressions are polynomials

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0
2,3,5,6 are the right answers
ivolga24 [154]2 years ago
4 0

Answer:

2,3,5,6

Step-by-step explanation:

You might be interested in
What additional information do you need to prove triangle NOP = triangle QSR?
Wewaii [24]
After careful consideration i think I have an answer... 
So if you notice, These two triangles are a reflection of each other. 
Now even though these two triangles equal one another, we still have to consider the fact that they are different. (one side is the opposite of another)
So lets just name all the sides that equal each other. 
∠N = ∠Q
NO = QS
QR = NP
PO = SR
∠S = ∠O 
∠P = ∠R 

(by the way i'm going to be saying {the reflective side} every time i want to refer to the side with the two lines :P) - so bare with me. 

So therefore this would mean that ∠P = ∠S would be false, since one angle is from the side that is reflected and the other isn't. Makes sense?

So lets look over at the answers...

A.) PN = SQ 
For this answer choice, PN is on the non reflective side, while SQ is on the reflective side. Soooo... This answer choice is wrong. 

B.) NO = QR
NO  is part of the  unreflective side, while QR is part of the reflective side. 
Therefore this answer is wrong. They must be part of the same side. 

C.) ∠P = ∠S 
∠P is on the unreflective side, while angle ∠S is on the reflective side. 
There fore this answer is also wrong. 

D.) ∠O = ∠S 
Now ∠O is on the reflective side while ∠S is on the reflective as well. 
There fore this answer is correct . 

YOUR ANSWER IS. 
D.) ∠O = ∠S 

Good Luck! :)


6 0
3 years ago
YOOO PLEASE HELPPPP!!!!
Evgesh-ka [11]

Given:

Base length of triangle = 40 units

Height of triangle = 9 units

Length of hypotenuse of triangle = 41 units

To find:

Find the value of Tan A

Steps:

Tan of an angle is equal to the opposite length by adjacent length.

So,

Tan A = \frac{opposite}{adjacent}

Tan A = \frac{9}{40}

Tan A = 0.225

Therefore, the exact value of Tan A is 0.225.

Happy to help :)

If you need any help, feel free to ask

4 0
2 years ago
N the diagram, and are horizontal lines and is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates of point D?
riadik2000 [5.3K]
<span>Given the diagram, where AB and EF are horizontal lines and CB is a vertical line segment. Given that FB : FC = 4 : 3, From the diagram, the coordinate of A is (-10, -8) and the coordinate of C is (-3. -1). We can also see that the coordinate of B is (-3, -8) (since CB is a vertical line means that B is the same x-value as C and AB is a horizontal line means that B is the same y-value as A) Recall that the coordinate of a point dividing a line segment in the ratio m:n is given by (x1 + m/(m+n) (x2 - x1), y1 + m/(m+n) (y2 - y1)) Thus, since FB : FC = 4 : 3, this means that point F divides the line segment BC in the ratio 4 : 3. Thus, the coordinate of F is given by (-3 + 4/(4+3) (-3 - (-3)), -8 + 4/(4+3) (-1 - (-8))) = (-3 + 4/7 (0), -8 + 4/7 (7)) = (-3, -4). Also, given that FB : FC = 4 : 3, this means that point D divides the line segment AC in the ratio 4 : 3. Thus, the coordinate of D is given by (-10 + 4/(4+3) (-3 - (-10)), -8 + 4/(4+3) (-1 - (-8))) = (-10 + 4/7 (7), -8 + 4/7 (7)) = (-6, -4). Therefore, the coordinates of point D is (-6, -4).</span>
5 0
3 years ago
20x3 - 45x2 + 21x + 25 \<br><br> 4x - 5
tiny-mole [99]

Answer:

80x3 - 180x2 + 109x - 20

—————————————

               4            

Step-by-step explanation:

4 0
3 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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