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gtnhenbr [62]
3 years ago
9

Help me I need to know before 8:20am today

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

184= 4(6y+4)

184= 24y +16

184 -16 = 24y

168=24y

168/24=y

y= 7

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HELP ME ASAPP<br><br><br> I have to turn it it in 7 minutes so plssss help me!!
lora16 [44]

Answer:

1/6

Step-by-step explanation:

Its a 1/6 chance it lands on the one u want

8 0
2 years ago
Read 2 more answers
Line b passes through points (5, 5) and (10, 8). Line c passes through points (4, 8) and (1, 13). Are line b and line c parallel
lora16 [44]

Answer:

Step-by-step explanation:

In going from (5, 5) to (10, 8), x (the run) increases by 5 and y (the rise) increases by 3.  Thus, the slope of the line connecting the first two points is m = 3/5.

In going from (1, 13) to (4, 8), x (the run) increases by 3 and y (the rise) decreases by 5.  Thus, the slope of the line connecting the first two points is m = -5/3

Because these results are negative reciprocals of one another, the two lines are PERPENDICULAR to one another.

3 0
3 years ago
Solve for x <br>possibly answer<br><br>12 <br>-7<br>5<br>-6​
Natali5045456 [20]

Answer:

12 is the answer. cause 5×12 is 60 and the missing angle is 60 degrees

3 0
3 years ago
You are designing an icon for a mobil app. Use the provided ruler to answer the following questions.
makkiz [27]

Answer:

a. Scale Perimeter : 2.5 centimeters

Actual Perimeter : 13 centimeters

Actual Area : 10.5 square centimeters

b. Actual Perimeter : 130 mm

Actual Area : 1,050 mm

Step-by-step explanation:

a. 2.5 mm = 0.25 cm

2 (1 + 0.25) = 2.5

2 (3.5 + 3) = 13

3.5 x 3 = 10.5

b. 3.5 cm = 35 mm 3 cm = 30 mm

2 (35 + 30) = 130

35 x 30 = 1050

7 0
2 years ago
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
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