What is the area of this trapezoid? Enter your answer in the box. ___cm2

Mathematics

1 answer:

dexar [7]2 years ago

8 0

Answer:

366

Step-by-step explanation:

area of a trapezoid is A=a+b/2(h)

multiplied by 16 and you get 366

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The height of a triangle is 3cm less than the length of its base and is area is 27m,find the height

Shkiper50 [21]

Area of a triangle=bh/2

27= x(x-3)/2
27= (x^2-3x)/2
54= x^2-3x
x^2-3x-54=0
(x-9)(x+6)=0

x=9, x=-6.
In this case, x must equal 9 since the base cannot be a negative number.

Final answer: Height=6 m

6 0

3 years ago

The length of one leg of a right triangle is 24 feet and the length of the hypotenuse is 40 ft what is the length of the other l

Rama09 [41]

To solve for the other leg, you need to use Pythagorean theory.

The theory states that C^2 = A^2 + B^2

In your case, you have to solve for B.
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The formula rewritten for B is $b= \sqrt{c^{2}-a^{2} }$

Now, you can solve.

$b= \sqrt{c^{2}-a^{2} }

b= \sqrt{40^{2}-24^2 }

b = \sqrt{1600 - 576}

b = \sqrt{1024}

b = 32$

Therefore, B = 32.

So the second leg is 32 feet.

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3 years ago

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p

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The answer is the last one - 48%

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The answer is x=11 !

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Read 2 more answers

From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle

Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ $1\text{ minute } =\frac{1}{60}\text{ degree }$