the square root of 10 would be 3.1
Answer:
635599482kg
Step-by-step explanation:
A gourmet chocolate candy has 7.00 gg of dietary fat in each 22.7-gg piece
for the 22.7 piece , the gg is 7 x 22.7 = 158.9gg in total
1gg = 2204622.6218488 lbs
158.9gg in total = 158.9 x 2204622.6218488 = 350314534.612
for the box of 4.00 lblb of candy
it is 350314534.612 x 4 = 1401258138.45lb
since our answer is needed in kilograms we convert 1401258138.45lb to kilograms
1lb = 0.453592kg
1401258138.45lb = 1401258138.45lb x 0.453592kg = 635599481.513 ≈ 635599482kg
Answer:
Step-by-step explanation:
Feel pleasure to help you.
Solve cos(4x)-cos(2x)=0 ∀ 0<=x<=2pi ..............(0)
Normal solution:
1. use the double angle formula to decompose, and recall cos^2(x)+sin^2(x)=1
cos(4x)=cos^2(2x)-sin^2(2x)=2cos^2(2x)-1 .................(1)
2. substitute (1) in (0)
2cos^2(2x)-1-cos(2x)=0
3. substitute u=cos(2x)
2u^2-u-1=0
4. Solve for x
factor
(u-1)(u+1/2)=0
=> u=1 or u=-1/2
However, since cos(x) is an even function, so solutions to
{cos(2x)=1, cos(-2x)=1, cos(2x)=-1/2 and cos(-2x)} ...........(2)
are all solutions.
5. The cosine function is symmetrical about pi, therefore
cos(-2x)=cos(2*pi-2x),
solution (2) above becomes
{cos(2x)=1, cos(2pi-2x)=1, cos(2x)=-1/2, cos(2pi-2x)=-1/2}
6. Solve each case
cos(2x)=1 => x=0
cos(2pi-2x)=1 => cos(2pi-0)=1 => x=pi
cos(2x)=-1/2 => 2x=2pi/3 or 2x=4pi/3 => x=pi/3 or 2pi/3
cos(2pi-2x)=-1/2 => 2pi-2x=2pi/3 or 2pi-2x=4pi/3 => x=2pi/3 or x=4pi/3
Summing up,
x={0,pi/3, 2pi/3, pi, 4pi/3}
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