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umka21 [38]
3 years ago
7

Simplify. Show your work. 13 +- 3918

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

I Got -3905

Step-by-step explanation:


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As the exercise says, the triangles are similar. So, we can set up proportions between correspondent sides.

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Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

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\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

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Answer:

Triangle QRS is an isosceles triangle because QR = RS.

Step-by-step explanation:

option D for Edgu hope this helps :)

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