Substitute the given point (3, -2) in each condition
(i) y < -3; y ≤ (2/3)x - 4
-2 < -3 → False
Therefore, it is not a solution.
[Since the values of x and y must satisfy both the conditions, if one of them does not satisfy the condition then it is not necessary to check the other one.]
(ii) y > -3; y ≥ 2/3x - 4
-2 > -3 → True
y ≥ 2/3x - 4
-2 ≥ -2 → True
Therefore, it is a solution.
(iii) y < -3; y ≥ 2/3x - 4
-2 < -3 → False
Therefore, it is not a solution.
(iv) y > -2; y ≤ 2/3x - 4
-2 > -2 → False
Therefore, it is not a solution.
Thereofore, the system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4. Hope it helps you.
I think you meant to say "relation" instead of "rebellion"? I'm not sure. Anyways, all you're looking for is the table with the x values -6, -4, -3, -1 which pair up with the y values 4, 0, 2, 2 in that exact order.
Table B does this exactly. The first row represents x = -6, y = 4. The second row represents x = -4, y = 0. The third row represents x = -3, y = 2. The fourth row represents x = -1, y = 2.
Answer: Choice B
and surely you know how much that is.
The answer is a-b with a corpondes triceptulas which =a+2+b+2 which septulases answer to 4a-b+a-b
