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Gekata [30.6K]
3 years ago
8

HELP!!Find the area of the pentagon.

Mathematics
2 answers:
just olya [345]3 years ago
7 0
A= 58.5 x 117
A= 6,844.5

hope i helped :)
maw [93]3 years ago
3 0

Answer:

ok first section off the two shapes that are easier to find like i did

ok so the area for a rectangle is length * width

the area of a triangle is height * base divided by 2

the answer is 117+58.5=175.5

the area of this "pentagon" is 175.5

Step-by-step explanation:

hope this helps you :)

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Explain how to model the division of –24 by –4 on a number line.
lianna [129]

Answer:

Here's one way to do it.

Step-by-step explanation:

-24 ÷ (-4)

-24 is the final number on the number line

-4 means you count by 4s on the number line moving backwards.

  1. Start at 0 facing forward.
  2. Move backwards in steps of four units from 0 to -24.
  3. Count the number of steps you took (six).

Answer: +6 (The sign is + because you are still facing forward).

8 0
3 years ago
Write a system of linear equations for the graph below
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1q+2x-1 liner #1 liner # is 18% one
5 0
4 years ago
Find a linear approximation of the function f(x)=\sqrt[3]{1+x} at a=0, and use it to approximate the numbers \sqrt[3]{.96} and \
34kurt
f(x)=\sqrt[3]{1+x}=(1+x)^{1/3}\implies f'(x)=\dfrac1{3(1+x)^{2/3}}

The linear approximation to f(x) around x=a is then

L(x)=f(a)+f'(a)(x-a)\approx f(x)

So the approximation centered at a=0 will be

L(x)=f(0)+f'(0)x=(1+0)^{1/3}+\dfrac x{3(1+0)^{2/3}}
L(x)=1+\dfrac x3

which means we have

\sqrt[3]{0.96}\approx L(0.96)=1+\dfrac{0.96}3=1.32

\sqrt[3]{1.02}\approx L(1.02)=1+\dfrac{1.02}3=1.34

Compare to the actual values of

\sqrt[3]{0.96}\approx0.9864

\sqrt[3]{1.02}\approx1.0066
4 0
4 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to have a populati
valkas [14]

Answer:

A sample of 139 should be taken.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Population standard deviation of $3,000.

This means that \sigma = 3000

How large a sample should be taken if the desired margin of error is $500?

A sample of n is needed.

n is found when M = 500. So

M = z\frac{\sigma}{\sqrt{n}}

500 = 1.96\frac{3000}{\sqrt{n}}

500\sqrt{n} = 1.96*3000

Dividing both sides by 500

\sqrt{n} = 1.96*6

(\sqrt{n})^2 = (1.96*6)^2

n = 138.3

Rounding up:

A sample of 139 should be taken.

7 0
3 years ago
Is this the right answer? Need help pls
ololo11 [35]
Yes! that is the correct answer I believe
4 0
3 years ago
Read 2 more answers
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