Answer:
135°
60°
75°
Step-by-step explanation:
hope this helps
Answer:
323
Step-by-step explanation:
![33b-40\\\\b=11\\\\33(11)-40\\\\363-40\\\\323](https://tex.z-dn.net/?f=33b-40%5C%5C%5C%5Cb%3D11%5C%5C%5C%5C33%2811%29-40%5C%5C%5C%5C363-40%5C%5C%5C%5C323)
A rhombus has four congruent sides. Without loss of generality, we denote the rhombus by the consecutive points PQRS.
1. Draw diagonal PR.
2. Consider triangle PQR. We conclude that PQ=RQ because a rhombus has four congruent sides. Triangle PRQ is isosceles => angles QPR and QRP are congruent.
3. Similarly, PS=RS. Triangle PSR is isosceles.
4. PR (diagonal) is common side, so triangles PQR is congruent to PSR (SSS).
5. Therefore angles QRP=QPR=SPR=SRP.
6. Since angles QPR=SPR, and SPR=QPR, we conclude that the diagonal PR is an angle bisector.
Finally, using similar arguments, we can show that diagonal QS bisects angles at Q and S.
Answer:
I Feel you. I despise it as well
Step-by-step explanation:
Answer:
h=-13/7
Step-by-step explanation:
2h-5-6h=12+3h-4
or, -4h-3h=8+5
or, -7h=13
or,h=13/-7
Therefore, h= -13/7