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Pachacha [2.7K]
3 years ago
12

In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts?

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
The answer is 126
 I think.... hope this helped:)
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Rebecca has 3 pairs of running shoes.She bought new shoelaces for each pair.How many shoelaces did she buy?
kvasek [131]

Answer: 6 shoelaces

Step-by-step explanation:

Since 1 pair of shoes has 2 shoelaces, 3 x 2 = 6

3 pairs x 2 shoelaces = 6 shoelaces

Hope this helped!

P.S. PLS give brailiest! I only have one brainliest!!

4 0
3 years ago
Read 2 more answers
8
Nimfa-mama [501]
3
—
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because the answer is 6 over -4 and it simplified is that answer.
3 0
3 years ago
Encontrar la media, mediana, moda y rango de los siguiente valores:
xenn [34]

Answer:

La mediana es 79 la moda es 87 la media 87 y él rango es 26

Step-by-step explanation:

Espero te ayude ;)

7 0
3 years ago
What is 7 divided by 1/9
MakcuM [25]
The answer 0.777777777
8 0
3 years ago
Read 2 more answers
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
Read 2 more answers
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