All categories

2 years ago

Simplify 6g + 8 - 3g - 2

Mathematics

1 answer:

Alinara [238K]2 years ago

7 0

Answer:

3g+6

Step-by-step explanation:

6g+8-3g-2

combine like terms

6g-3g= 3g

3g+8-2

8-2= 6

3g+6

You might be interested in

Somebody help pls Complete the table by filling in the multiplicative inverse of the numbers below

Harlamova29_29 [7]

Answer:

2---> 1/2

1/5 ----> 5

-4 ----> 1/-4

1 2/5 = 7/5 ----> 1/(7/5) = 5/7

Step-by-step explanation:

8 0

2 years ago

The graph of F(x), shown below, resembles the graph of G(x) x2, but it has

Bingel [31]

Correct answer is: F(x)=-x^2-3

Step-by-step explanation:

We are given a function:

The graph of is also shown in the given question figure.

It is a parabola with vertex at (0,0).

Sign of is positive, that is why the parabola opens up.

General equation of parabola is given as:

Here, in G(x), a = 1

Vertex (h,k) is (0,0).

As seen from the question figure,

The graph of F(x) opens down that is why it will have:

Sign of as negative. i.e.

And vertex is at (0,-3)

Putting the values of a and vertex coordinates,

Hence, the equation of parabola will become:

7 0

2 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

3 years ago

Two ratios by entering less than greater than or equal than 16 to 15, 30 to 80

Mumz [18]

Answer:

6:15>30:80

Step-by-step explanation:

The ratio;

6:15 written in the form x/1 is equivalent to 2/5 or 0.4

30:80 written in the form x/1 is equal to 3/8 or 0.375

0.4 is greater than 0.375

Therefore;

<u>6:15>30:80</u>

6 0

3 years ago

HELP, PLEASE, WILL GIVE BRAINLIEST

Juli2301 [7.4K]

The answer would be B
Because $2.10×7 = 14.7 and $1.85×6 = 11.1 so the new were add 14.7+11.1 Hope this helps

4 0

2 years ago