3 years ago

What is the sum of the geometric sequence 1,-6,36... if there are 6 terms

1 answer:

7 0

$a_1=1;\ a_2=-6;\ a_3=36;\ ...\\\\r=a_2:a_1\to r=-6:1=-6\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\a_1=1;\ r=-6;\ n=6\\\\subtitute\\\\S_6=\dfrac{1(1-(-6)^6)}{1-(-6)}=\dfrac{1-46656}{1+6}=\dfrac{46655}{7}=6665$

You might be interested in

Use the Rational Root Theorem to list all possible rational roots for the equation.

kicyunya [14]

The answer would be B and here’s the steps :)

5 0

3 years ago

Help me fast ..................

Kisachek [45]

If two angles and included side of one triangle are equal to two angles and the included side of the other triangle , then the two triangles are congruent (ASA rule).

in figure

consider triangle ABD and ACD
Angle BAD = angle CAD
AB = AC
Angle B = angle C
triangle ABD congruent to Triangle ACD ( by ASA rule)

7 0

3 years ago

Juan says that 8, 1 3/4, and -12 are all integers. Is he correct? Explain your answer. Please help me fast

monitta

No, he is not right.

Integer is a number that can be written without a fractional component, and 1 3/4 doesn't.

Here's an image for you to better understand.