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3 years ago

What is the sum of the geometric sequence 1,-6,36... if there are 6 terms

1 answer:

7 0

$a_1=1;\ a_2=-6;\ a_3=36;\ ...\\\\r=a_2:a_1\to r=-6:1=-6\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\a_1=1;\ r=-6;\ n=6\\\\subtitute\\\\S_6=\dfrac{1(1-(-6)^6)}{1-(-6)}=\dfrac{1-46656}{1+6}=\dfrac{46655}{7}=6665$

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A) y B) y>x C) y+x = 1 D) y/x = 1

Bond [772]

Answer:

The answer should be C

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3 years ago

What is the value of x?

deff fn [24]

The value of x is the variable of the number it is closer to

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4 years ago

What is the equation of a line that is parallel to y=2/3x+4 and passes through the point (3,7)

jeka57 [31]

Answer:

y=2/3x+5

Step-by-step explanation:

Parallel lines share the same slope so we already know the slope: 2/3.

Now we need to find the y-intercept for the equation. To do that, replace 4 with b. We have y=2/3x+b.

To find out what b is, we need to plug in the x and y values we are given into the current equation. We get 7=2/3(3)+b.

7=2+b

5=b

Now we can put all the information we have together.

y=2/3x+5

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3 years ago

Find the common factors of the given terms: 2y, 22xy. Ok

Lesechka [4]

Answer:

2y

Step-by-step explanation:

this is common factor of both the terms

because 2y divides both term

hope it helps

5 0

3 years ago

The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil

forsale [732]

Answer:

$IQR=4$

Step-by-step explanation:

We have been given a data set that represents the number of rings each person in a room is wearing as: 0, 2, 4, 0, 2, 3, 2, 8, 6. We are asked to find the interquartile range of the data.

Let us arrange our data points from least to greatest order.

0, 0, 2, 2, 2, 3, 4, 6, 8.

Let us find median of our data set. Since our data set has 9 data points, therefore, median of our given data set will be value of 5th term, that is 2.

Now let us find lower quartile, which is also known as the median of the data points to the left of median.

We have 4 data points to the left of our median, so our lower quartile will be average of 2nd and 3rd data point.

$Q_1=\frac{0+2}{2}=\frac{2}{2}=1$

Now let us find upper quartile of our given data set, which is the median of the data points to the right of median.

We have 4 data points to the right of the median, so our upper quartile will be the average of 7th and 8th data point.

$Q_3=\frac{4+6}{2}=\frac{10}{2}=5$

Since we know that interquartile range is the difference between upper and lower quartile.

$IQR=Q_3-Q_1$

$IQR=5-1$

$IQR=4$

Therefore, IQR of our given data set is 4.

8 0

3 years ago

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