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viktelen [127]
3 years ago
10

11. Propane (C3Hg) is a fuel commonly used in gas grills.

Chemistry
1 answer:
Mrac [35]3 years ago
5 0

Answer:

81.71%

Explanation:

One mole of propane contains 3 moles of carbon atoms and 8 moles of hydrogen atoms, as seen from the molecular formula of C_3H_8. In order to calculate the percent of carbon in propane by mass, we need to remember that %w/w (or percent mass) formula states that:

\omega=\frac{m_{component}}{m_{total}}\cdot100\%

That is, we need to divide the mass of the component of interest by the total mass of the compound and multiply by 100 to obtain the percentage.

For simplicity, let's take 1 mole of propane and find the mass of 1 mole (hence, we'll be finding the molar mass of propane). To do that, we add the 3 molar masses of carbon and 8 molar masses of hydrogen to obtain a total of:

M_{C_3H_8}=3M_C+8M_H=3\cdot12.011 \frac{g}{mol}+8\cdot1.00784\frac{g}{mol}=44.096 \frac{g}{mol}

Now that we have the molar mass of propane, we also need to find the total mass of carbon in 1 mole of propane. We know that we have a total of 3 moles of carbon which corresponds to:

M_C=3\cdot12.011 \frac{g}{mol}=36.033 \frac{g}{mol}

Dividing the mass of carbon present by the total mass of the compound will yield the mass percentage as defined by the formula we introduced:

\omega_C=\frac{36.033\frac{g}{mol}}{44.096 \frac{g}{mol}}\cdot 100\%=81.71\%

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4 0
3 years ago
WILL GIVE BRAINLIEST
dedylja [7]

Answer:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c=4.18Jg∘C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

q - heat absorbed

m - the mass of the sample

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In your case, you will have

q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C

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4 0
3 years ago
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enyata [817]
0.004382166 Make sure to round to the right amount of Sig Figs
8 0
3 years ago
Answer Quick
kow [346]

Answer:

20.9%

Explanation:

  • The percentage by mass of solution is given by dividing the mass of solute in grams by the mass of solution in grams then multiplying it by 100%.

% Mass of solution = mass of solute/mass of solution × 100%

                               = (27.0 g/ 129.0 g) × 100%

                               = 20.93%

                               = 20.9%

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