We know that if two lines are Perpendicular then Product of Slopes of both of these Perpendicular lines should be Equal to -1
Given : Equation of 1st Perpendicular line is -x + 3y = 9
This can be written as :
3y = x + 9
y = x/3 + 3
Comparing with standard form : y = mx + c
we can notice that slope of 1st Perpendicular line = 1/3
Slope of 1st Line × Slope of 2nd line = -1
1/3 × Slope of 2nd line = -1
Slope of 2nd line = -3
We know that the form of line passing through point (x₀ , y₀) and having slope m is :
y - y₀ = m(x - x₀)
Here the 2nd Perpendicular line passes through the point (-3 , 2)
x₀ = -3 and y₀ = 2 and we found m = -3
⇒ y - 2 = -3(x + 3)
⇒ -3x - 9 = y - 2
⇒ -3x - y = 7
Maybe you should try 18 it might work because it will all be equal
Answer:
Answer choice a.
Step-by-step explanation:
Let's do part of the work of solving the given system:
6x + 2y = −6
3x − 4y = −18
Multiply the first equation by 2 so as to make the coefficient of y = to 4:
12x + 4y = -12
Combine this result with the second equation:
12x + 4y = -12
3x − 4y = −18
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15x = -30
Note that these results are precisely the same as the equations in Answer Choice a.
Log₅ 20 = 4
Written in exponent form: 20 = 5⁴, which is wrong since 20 ≠ 5⁴
