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1 answer:
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Answer:
21 bushels of sweet corm weight 735 pounds.
Step-by-step explanation:
Given:
Weight of 21 bushels of sweet corn is obtained by multiplying the unit weight to the number of bushels required.
Unit weight of sweet corn is the weight of 1 bushel of sweet corn.
Weight of 1 bushel of sweet corn = 35 pounds
So, weight of 21 bushels of sweet corns = pounds.
Therefore, 21 bushels of sweet corn weigh 735 pounds.
Answer:
the student should score atleast 229 to be among the top 10%.
Step-by-step explanation:
in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)
after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.
we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)
looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)
the student should score atleast 229 to be among the top 10%.